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crimeas [40]
3 years ago
8

A boy whirls a stone with uniform speed in a horizontal circle of radius 2 m and at height 2 m above the ground. The string brea

ks and the stone flies off horizontally and strikes the ground after traveling a horizontal distance of 2 m. What was the magnitude of the stone's centripetal acceleration (in m/s2) when it was in circular motion?
Physics
1 answer:
svp [43]3 years ago
8 0

Answer:

Explanation:

162.7 m/s²

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Why do the planets appear in different locations in the night sky while the pattern of stars in a constellation stays the same?
Goshia [24]
I'm sure you've noticed that an airplane high in the sky, far away
from you, looks like it's moving very slowly.  At the same time,
somebody passing you on a skateboard whizzes past you at
high speed.  The farther away something is from you, the slower
it appears to move.

The nearest star outside the solar system is almost 32 thousand times
as far away from us as the farthest visible planet (Saturn) is, and all of the
other stars are farther than that. 

That's why you have to wait a few thousand years before you notice
that the shape of a constellation has changed.

To put it a slightly different way . . . Everything is in motion.  The motion is
more noticeable for nearby things, and less noticeable for farther-away things. 
Objects within our solar system are the only ones near enough so that a human
lifetime is a long enough period in which to notice the change in their position.
Even Pluto moves less then 1.5° against the 'background' stars in a whole year.

This all makes me feel small.  How about you ?
7 0
4 years ago
Read 2 more answers
PLEASE HELP!
lutik1710 [3]

Answer:

Thats her fault.........................b

Explanation:

6 0
3 years ago
Three pendulums all have the same length and start from the same height. The first pendulum is very light and has a mass of 67 g
vovikov84 [41]

Answer:

All three pendulum will attain same velocity

Explanation:

All three pendulum will attain same velocity irrespective of their mass difference in isolated system (means where air drag are negligible) and at same length

As you know when velocity is calculated we can not take mass into account.  

3 0
3 years ago
helpppp I just saw my crush when I was walking out of a supermarket and like I was looking a mess so now I'm just wondering how
UkoKoshka [18]

Answer:

okay

Explanation:

(wish i could help but im just answering for points)

3 0
3 years ago
A damped mass/spring system takes 14.0 s for its amplitude of the oscillator to decrease by a factor of 9. By what factor does t
fiasKO [112]

Answer:

The correct answer is "0.246".

Explanation:

Given that the amplitude is decreased by a factor of 9, then

A \rightarrow (A-\frac{A}{9} )

A \rightarrow \frac{8A}{9}

As we know,

Energy will be:

⇒  E_{1}=\frac{1}{2}KA^2

and,

⇒  E_{2}=\frac{1}{2}K(\frac{8A}{9} )^2

          =\frac{64KA^2}{162}

⇒  \Delta E=E_1-E_2

On putting the estimated values, we get

           =\frac{1}{2}KA^2-\frac{64KA^2}{162}

⇒  \frac{\Delta E}{E}=\frac{\frac{20}{162}KA^2}{\frac{1}{2}KA^2}

          =\frac{40}{162}

          =0.246

3 0
3 years ago
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