Answer:
The required 18th term of the given sequence will be -160
Step-by-step explanation:
The A.P. is given to be : 44, 28, 12, -4, ....
First term, a = 44
Common Difference, d = 28 - 44
= -12
We need to find the 18th term of the sequence.
![a_n=a+(n-1)\times d\\\\\implies a_{18}=44+(18-1)\times -12\\\\\implies a_{18}=44+ 17 \times -12\\\\\implies a_{18}=44-201\\\\\implies a_{18}=-160](https://tex.z-dn.net/?f=a_n%3Da%2B%28n-1%29%5Ctimes%20d%5C%5C%5C%5C%5Cimplies%20a_%7B18%7D%3D44%2B%2818-1%29%5Ctimes%20-12%5C%5C%5C%5C%5Cimplies%20a_%7B18%7D%3D44%2B%2017%20%5Ctimes%20-12%5C%5C%5C%5C%5Cimplies%20a_%7B18%7D%3D44-201%5C%5C%5C%5C%5Cimplies%20a_%7B18%7D%3D-160)
Hence, The required 18th term of the given sequence will be -160