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Dominik [7]
3 years ago
12

3/13 as a decmal ronded to the nearest hundeth

Mathematics
1 answer:
Illusion [34]3 years ago
8 0
Simple...

you have: \frac{3}{13}

Dividing-->>

0.23076923

But, remember, you're rounding to the nearest hundreth...

0.23

Thus, your answer.
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In which direction does the parabola open?
svetoff [14.1K]
The parabola opens up as the largest term has a positive leading co-efficent


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3 years ago
You want to put $2,500 in a simple interest account.It has a 4% annual interest rate.How long will it take you to earn $200 in i
prohojiy [21]
It will take 2 years.

Year 1 :
4% 2.5k = 2.5k/100 × 4 = $100 in interest

$2.5k + $0.1k = $2.6k

Year 2 :
4% 2.6k = 2.6k/100 × 4 = $104 in interest

$100 + $104 = $204 > $200

There may be a simpler way to solve this using a formula for example, but I just solved this step by step. Please feel free to ask if you have any questions
7 0
3 years ago
A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

3 0
3 years ago
1.Find the area of a circle with the radius of 48mm
OLga [1]

Answer:

hope it helps you see the attachment for further information....

3 0
3 years ago
solve |5x - 1| < 1 a. {x|0 < x < 2/5} b. {x|x < 0 or x > 2/5} c. {x|-2/5 < x < 2/5}
aliina [53]
<span>|5x - 1| < 1
-1 < 5x - 1 < 1
-1 + 1 < 5x < 1 + 1
0 < 5x < 2
0/5 < x < 2/5
0 < x < 2/5
</span>
8 0
3 years ago
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