<span>Before this we need to know the correlation between volume in liters (l) and in cubic cm (cmł), 1 l = 1000 cmł. Then we need to under stand the correlation between cubic cm (cmł) and cubic mm (mmł), 1000 cmł = 1 000 000 mmł.
Finally all we have to do is calculating the volume of the cube, because all side have the same length, the math is simple. Calculating the content for any rectangle shape is width times length times height.
So in this case 20 cm * 20 cm * 20 cm = 8000 cmł as seen before this is a total of 8000 cmł = 8 000 000 mmł or 8 liters of fluid.</span>
Answer:
a) HCN - hybridization sp
b) C(CH₃)₄ - hybridization sp³
c) H₃O⁺ - hybridization sp³
d) - CH₃ - hybridization sp³
Explanation:
Hybridization occurs to allow an atom to make more covalent bonds than the original electronic distribution would allow or to allocate ligands in an energetically stable geometry.
Carbon can have thre hybridization states: sp³ , sp² and sp.
Oxygen usualluy has an sp³ hybridization.
In order to determine the hybridization, we need to consider the number of atoms attached to the central atom and the number of lone pairs.
The figure attached shows the species and the hybridization of their central atoms.
Answer:
47.1 L.
Explanation:
- To solve these problems, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 234.0 kPa/101.325 ≅ 2.31 atm) .
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 3.9 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 67.0 °C + 273.15 = 340.15 K).
The volume of the gas = nRT/P.
<em>∴ V = nRT/P </em>= (3.9 mol)(0.082 L.atm/mol.K)(340.15 K)/(2.31 atm) = <em>47.1 L.</em>
Answer:
pH1=4.98
pH2=5.06
pH3=4.90
Explanation:
Hello there!
In this case, it is possible to analyze the problem according to the Henderson-Hasselbach equation:
Whereas the pKa = 4.88 and the base is identified as the sodium propionate and the acid as the propionic acid. Now, for the pH of the buffer we simply plug the given data in the formula to obtain:
Next, since the addition of 0.02 mol NaOH results in the consumption of 0.02 moles of acid and the formation of 0.02 moles of base, we use the following modification for the HH equation:
Which of course, increases the pH as NaOH is a strong base. Finally, for the addition of 0.02 mol HI, a consumption of the base and formation of the acid are implied since HI is a strong acid, for which the pH turns out to be less than the initial 4.98:
Best regards!
Answer: Option 12.5 is the correct answer.
Explanation:
The given reaction is as follows.
As it is a combustion reaction so, nitrogen will not take part in it and hence, it will remain the same on both sides of the reaction.
Also, it is known that in a combustion reaction oxygen reacts with a hydrocarbon and results in the formation of carbon dioxide and water. Therefore, for the above reaction we write the complete reaction equation as follows.
or, as nitrogen is not taking part in the reaction.
Number of atoms on reactant side are as follows.
C = 8
H = 18
O = 2
Number of atoms on product side are as follows.
C = 1
O = 3
H = 2
Therefore, to balance this equation we multiply oxygen on reactant side by 12.5. Also, we multiply carbondioxide by 8 and water by 9 on product side. Hence, the complete balanced chemical equation is as follows.