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3 years ago

Mercury, Venus, Earth, and Mars are all ______ planets.

1 answer:

8 0

Mercury, Venus, Earth, and Mars are all ___inner___ planets. This is because they are all within the asteroid belt.

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The difference between a molecule and a compound is that a compound is made up of atoms from

defon

Answer:

The difference between a molecule and a compound is that a compound is made up of atoms from different elements.

3 0

3 years ago

A train traveling at 27.5 accelerates to 42.4 m s over 75.0 s What is the displacement of the train in this time period A train

jarptica [38.1K]

Answer:

The displacement of the train in this time period is 2,616.86 m.

Explanation:

A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.

In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).

An independent equation of useful time in this type of movement is:

$vf^{2} =vi^{2} +2*a*d$ Expression A

where:

vf = final velocity
vi = initial velocity
a = acceleration
d = distance

The equation of velocity as a function of time in this type of movement is:

vf=vi + a*t

So the velocity can be calculated as: $a=\frac{vf-vi}{t}$

In this case:

vf=42.4 m/s
vi=27.5 m/s
t=75 s

Replacing in the definition of acceleration: $a=\frac{42.4 m/s-27.5 m/s}{75 s}$

a=0.199 m/s²

Now, replacing in expression A:

$(42.4 m/s)^{2} =(27.5 m/s)^{2} +2*(0.199 m/s^{2}) *d$

Solving:

$d= \frac{(42.4 m/s)^{2} - (27.5 m/s)^{2} }{2*(0.199 m/s^{2}) }$

d= 2,616.86 m

The displacement of the train in this time period is 2,616.86 m.

4 0

3 years ago

A student walks 3.0m [E] and then 4.0m [N] in 5.0s.

ANEK [815]

Answer:

average speed and velocity are 0.5m/s (squared)

8 0

3 years ago

A block is at rest on the incline shown in the gure. The coefficients of static and kinetic friction are 0.6 and 0.51, respec- t

Alekssandra [29.7K]

Normal reaction force on the block while it is at rest on the inclined plane is given as

$F_n = mgcos\theta$

here we know that

m = 46 kg

$\theta = 29^o$

now we will have

$F_n = 46*9.8*cos29 = 394.3 N$

now the limiting friction or maximum value of static friction on the block will be given as

$F_s = \mu_s * F_n$

$F_s = 0.6 * 394.3 = 236.56 N$

Above value is the maximum value of force at which block will not slide

Now the weight of the block which is parallel to inclined plane is given as

$F_{||} = mg sin\theta$

here we know that

$F_{||} = 46*9.8 sin29 = 218.55 N$

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.

So here friction force on the given block will be same as its component on weight which is 218.55 N

5 0

3 years ago

Which electrical protective device is designed to detect a difference in current between circuit wires and interrupt the circuit

Ilya [14]

That's the description of a ground fault circuit interrupter (GFCI).

The choices you posted seem to belong to a different question.

8 0

3 years ago