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3 years ago

14

How do you calculate the change in speed?

2 answers:

Dennis_Churaev [7]3 years ago

8 0

v = d/t

d = distance

t = time

the change in speed (Δv)

$\tt \Delta v=\dfrac{d_2-d_1}{t_2-t_1}$

marta [7]3 years ago

3 0

Multiply the acceleration by time to obtain the velocity change: velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h .

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A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target

stiks02 [169]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

$\theta=35^{\circ}$

a.Let $v_0$ be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

$v_x=v_0cos\theta=v_0cos35$

$v_y=v_0sin\theta=v_0sin35$

$x=v_0cos\theta\times t=v_0cos35\times t$

$t=\frac{30}{v_0cos35}$

$h=v_yt-\frac{1}{2}gt^2$

Substitute the values

$1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2$

$1.8=30tan35-\frac{6574.6}{v^2_0}$

$\frac{6574.6}{v^2_0}=21-1.8=19.2$

$v^2_0=\frac{6574.6}{19.2}$

$v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s$

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

$t=\frac{30}{18.5cos35}$

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

7 0

3 years ago

Identify the types of simple machine given below .<br>a)scissors b)axe c)driller<br>

NARA [144]

Answer:

there should some picture to identify right?

pls edit your question and insert the picture..

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3 years ago

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A force of 100N is applied to move an object a horizontal distance of 20m to the right. The work done by this force on the objec

horsena [70]

WORKDONE = FORCE * DISPLACEMENT
W=F*S
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WORKDONE = 100*20
WORKDONE=2000
ITS S.I UNIT IS JOULE OR J
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3 years ago

What are the benefits of solar cookers?

Elanso [62]

Answer:

Using clean, renewable, and readily available solar energy as fuel.

Preserving natural resources by not requiring the use of wood or other biomass fuels to cook.

Not producing dangerous emissions which pollute local environments and contribute to climate change.

Explanation:

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3 years ago

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A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle

emmasim [6.3K]

<u>Given data:</u>

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ => R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping <em>μs = tan Φ, Φ = Θ </em>

<em>Pmin = W sin( α +Θ )</em>

<em> = W[ sin α.Cos Θ + cos α.sin Θ]</em>

<em> = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]</em>

<em> = 460.9 N</em>

<em>Minimum push required to move the box up the ramp is 460.9 N</em>

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3 years ago