The right answer for the question that is being asked and shown above is that: "A. Reverse the way the wire is connected to the poles of the battery." the statement describes a step that will help troubleshoot and work toward the solution of this problem is that <span>Reverse the way the wire is connected to the poles of the battery.</span>
5 n to the right I think Hope this helps
Answer:

Explanation:
According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

Here
is the magnetic force and
is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so
. Replacing and solving for B:

Answer:
A star's brightness also depends on its proximity to us. The more distant an object is, the dimmer it appears. Therefore, if two stars have the same level of brightness, but one is farther away, the closer star will appear brighter than the more distant star - even though they are equally bright!
Can I have brainliest?
Answer:
AB = DE <CD <BC
Explanation:
This is an exercise in kinetics, the accelerations defined as the change in velocity over the time interval, therefore the accelerations of a vector.
Because the acceleration is a vector, it has two parts, the modulus that the numerical value of the magnitude and the direction, a change in any of them implies the existence of a relationship.
Let's apply these reasoning to our problem.
AB Path
this path is straight and as they indicate that the constant speed the acceleration is zero
DE path
This path is straight and since the velocity is constant the zero steps
BC path
This path is a curve and the velocity modulus is constant, but its directional changes therefore there is an acceleration called centripetal, given by the expression
= v² / r
where r is the radius of the curve and the direction of acceleration is towards the center of the curve
CD path
This path is a curve and it also has centripetal acceleration, as can be seen in the drawing, the radius of the curve is greater than in section BC, therefore the acceleration is less
>
In summary lower accelerations are
AB = DE <CD <BC