A train sounds its whistle as it approaches a tunnel in a cliff. The whistle produces a tone of 650 Hz and the train travels wit
1 answer:
Answer: = 692.82Hz
Explanation: This question of ours is based on Doppler effect.The Doppler effect states that<em> if a source is producing sound at a specific frequency to an observer and there is a relative motion between the observer and the source, the frequency of sound perceived by the observer will be different from that of the original from the source. </em>
This represented mathematically below as
where
= observed frequency = ?
f = original frequency of sound source = 650Hz
v = speed of sound in air = 343m/s
= velocity of observer relative to the source = 0m/s ( the observer is standing, thus meaning he is not moving)
= velocity of sound source relative to the observer = 21.2m/s
by putting all of these in the formulae, we have that
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Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem =
fem = - d (B l y) / dt = - B lv
B =
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West
Answer:
Plss see attached file
Explanation:
