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Stels [109]
3 years ago
10

What is true of a solution of 2.0 M NaCl(aq)?

Chemistry
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

The unit of M (molarity) is a unit of moles per liter of solution. So, the solution contains 2.0 moles of NaCl per 1 liter of solution.

alexgriva [62]3 years ago
6 0

Answer : The correct option is, It contains 2.0 moles of NaCl per 1 liter of solution.

Explanation : Given,

Molarity of NaCl solution = 2.0 M

Molarity : It is defined as the number of moles of solute present in one liter of solution. The unit of molarity is, mole/L or M.

Formula used :

\text{Molarity}=\frac{\text{Moles of }NaCl}{\text{Volume of solution in liters}}

2.0 M means that 2 moles of NaCl present in one liter of solution.

Therefore, the correct option is, It contains 2.0 moles of NaCl per 1 liter of solution.

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A compound containing chromium, Cr; chlorine, Cl; and oxygen, O, is analyzed and found to be 33.6% chromium, 45.8% chlorine, and
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Answer

The empirical formula is CrO₂Cl₂

Explanation:

Empirical formula is the simplest whole number ratio of an atom present in a compound.

The compound contain, Chromium=33.6%

                                         Chlorine=45.8%

                                          Oxygen=20.6%

And the molar mass of Chromium(Cr)=51.996 g mol.

                 Chlorine containing molar mass (Cl)= 35.45    g mol.

                 Oxygen containing molar mass (O)=15.999  g mol.

Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

Cl= \frac{1}{35.45} \times45.8=1.29 mol.

O=\frac{1}{15.99} \times=1.28 mol.

Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

Cl= \frac{1.29}{0.64} =2

O= \frac{1.28}{0.64} =2

Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)

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4 years ago
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Answer:

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Explanation:

hope this helps

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