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adelina 88 [10]
3 years ago
6

For chemistry purposes we will always measure delta Ts (temperature changes) with which scale?

Chemistry
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

Kelvin

Explanation:

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1.42 mol sample of neon gas at a temperature of 13.0 °C is found to occupy a volume of 25.5 liters. The pressure of this gas sam
Dima020 [189]

Answer: 996 mmHg

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = ?

V= Volume of the gas = 25.5 L

T= Temperature of the gas = 13°C = (273+13) K  = 286K

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= 1.42

P=\frac{nRT}{V}=\frac{1.42\times 0.0821\times 286}{25.5}=1.31atm=996mmHg      (760mmHg=1atm)

Thus pressure of this gas sample is 996 mm Hg.

3 0
3 years ago
A tow truck does 10,000 J of work in 5 seconds. Calculate the power.
chubhunter [2.5K]

Answer:

power is work/time so 10,000j/5s=2000J/s

5 0
3 years ago
What is difference between ∆H and ∆H°
Elena-2011 [213]

If it is shown as ∆H , then it means that a specific chemical reaction is undergoing heat in Kelvin(K). If it is shown as ∆H° , then it means that a specific chemical reaction is undergoing heat in Celsius(C⁰).

Hope this is the answer you are looking for mate!

If it is correct then please mark my answer as the brailiest! :)

5 0
3 years ago
A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem
Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat gained  = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = 0.0923cal/g^oC      

\Delta T=\text{Change in temperature} 

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC

Now put all the given values in the above formula, we get the final temperature of copper.

299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)

T_{final}=87.29^oC

Therefore, the final temperature of the copper is, 87.29^oC

4 0
3 years ago
12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?
bazaltina [42]

Answer:

u=4.57x10^5GHz

Explanation:

Hello.

In this case, given the formula:

E=h*u

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\  \\u=4.57x10^{14}s^{-1}

Or also:

u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz

Best regards.

5 0
3 years ago
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