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3 years ago

What is a common event due to transform plate movement at the San Andreas Fault Zone?

Chemistry

2 answers:

Genrish500 [490]3 years ago

8 0

Answer:

Earthquakes

Explanation:

took the test

AVprozaik [17]3 years ago

8 0

Answer:

Earthquakes

Hope this helps:3

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What is the energy of an electromagnetic wave with a frequency of 8•10^12 Hz?

aniked [119]

Hello!

Find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) = $6.626*10^{-34}\:J * s$

f (radiation frequency) = $8*10^{12}\:Hz$

Therefore, we have:

$E = h*f$

$E = 6.626*10^{-34}*8*10^{12}$

$E = 53.008*10^{-34+12}$

$E = 53.008*10^{-22}$

$\boxed{\boxed{E = 5.3008*10^{-21}\:Joule}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

8 0

2 years ago

How many atoms of carbon are combined to with 2.81 moles of hydrogen atoms in a sample of the compound ethane, C2H6?

puteri [66]

Answer:

5.64×10²³ atoms C

Explanation:

Convert moles of H to moles of C:

2.81 mol H × (2 mol C / 6 mol H) = 0.937 mol C

Convert moles of C to atoms of C:

0.937 mol C × (6.02×10²³ atoms C / mol C) = 5.64×10²³ atoms C

5 0

3 years ago

True or False? Nitrogen can get back into the atmosphere when dead plants and animals are decomposed by bacteria. The bacteria b

Readme [11.4K]

Answer: True

Explanation:

6 0

3 years ago

Read 2 more answers

Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -> 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how

bazaltina [42]

$\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O$

13mol of O_2 reacts with 2mols of C_4H_10.
7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

$\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}$

$\\ \tt\hookrightarrow \dfrac{400}{58}$

$\\ \tt\hookrightarrow 6.89mol$

Now

Moles of O_2

$\\ \tt\hookrightarrow 7.5(6.89)=51.6mol$

Mass of O_2

$\\ \tt\hookrightarrow 51.6(32)=1651.2g$

4 0

2 years ago

What mass of cu(s) is electroplated by running 26.5 a of current through a cu2+(aq) solution for 4.00 h?

kramer

T = 14400 s
26.5 x 14400=381600 C
381600/96500=3.95 Faradays
Cu2+ + 2e- = Cu
3.95 faradays ( 1 mol/ 2 Faradays) = 1.97
mass = 1.97 x 63.55 g/mol=125 g

moles Au = 33.1 / 196.967 g/mol=0.168
Au+ + 1e- = Au
0.168 ( 1 Faraday/ 1mol)= 0.168 Faraday
0.168 x 96500=16217 Coulombs
16217 / 5.00=3243 s => 54 min

7 0

3 years ago