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chubhunter [2.5K]
1 year ago
14

Which gives the work done by a torque during angular displacement?

Physics
1 answer:
Nutka1998 [239]1 year ago
4 0

Only when the torque is constant the work done is done during angular displacement. So the correct option is d.

Work done by the force is calculated as the dot product of force and  angular displacement of the point of application of force. It is equal to the change in rotational kinetic energy of the body.

Work done by a torque can be calculated by taking an analogy from work done by force.

Work done = torque × angular displacement

So work is done by a torque during angular displacement only when torque is constant.

If a torque applied on a body rotates it through an angle ω, the work done by torque is

W = ζ × ω

To know more about the work done by torque refer to the link given below:

brainly.com/question/17083207

#SPJ4

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Answer:

yes

Explanation:

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How many kisses is 50 hectokisses?<br><br> What would you be if you earn a megabuck year?
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What is the equation for frequency, wavelength, and speed of a wave?
Nastasia [14]

Answer:

       λ = v/f

Explanation:

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3 years ago
A 12.0 cm object is 9.0 cm from a convex mirror that has a focal length of -4.5 cm. What is the distance of the image from the m
Rasek [7]

Answer:

- 3 cm

Explanation:

From the mirror formula;

1/f = 1/v + 1/u ; where f is the focal length, v is the image distance, and u is the object distance.

1/-4.5 = 1/9 + 1/v

1/v = -1/4.5 - 1/9

    = -1/3

Therefore;

v = -3 cm

Hence;

Image distance is - 3cm

5 0
3 years ago
Calculate the magnitude of the acceleration of the box if you push on the box with a constant force 170.0 N that is parallel to
Degger [83]

The acceleration of the  box up the ramp is 9.65 m/s².

<h3>What is the magnitude of acceleration of the box?</h3>

The magnitude of the acceleration of the box is calculated by applying Newton's second law of motion as shown below;

F(net) = ma

where;

  • m is the mass of the box
  • a is the acceleration of the box

The net force on the box is calculated as follows;

F(net) = F - Ff

F(net) = F - μmgcosθ

where;

  • θ is the inclination of the plane
  • μ is coefficient of friction

F(net) = 170 -  (0.3 x 15 x 9.8 x cos55)

F(net) = 144.7

The acceleration of the box is calculated as;

a = F(net) / m

a = (144.7) / (15)

a = 9.65 m/s²

Thus, the acceleration of the  box up the ramp is 9.65 m/s².

Learn more about acceleration here: brainly.com/question/14344386

#SPJ4

8 0
1 year ago
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