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chubhunter [2.5K]
2 years ago
14

Which gives the work done by a torque during angular displacement?

Physics
1 answer:
Nutka1998 [239]2 years ago
4 0

Only when the torque is constant the work done is done during angular displacement. So the correct option is d.

Work done by the force is calculated as the dot product of force and  angular displacement of the point of application of force. It is equal to the change in rotational kinetic energy of the body.

Work done by a torque can be calculated by taking an analogy from work done by force.

Work done = torque × angular displacement

So work is done by a torque during angular displacement only when torque is constant.

If a torque applied on a body rotates it through an angle ω, the work done by torque is

W = ζ × ω

To know more about the work done by torque refer to the link given below:

brainly.com/question/17083207

#SPJ4

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True, also fizzing and heat being released
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You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
olga nikolaevna [1]

Answer:112.82 m/s

Explanation:

Given

range of arrow=68 m

Angle=3^{\circ}

as the arrow travels it acquire a vertical velocity v_y

v_y=u+at

v_y=0+9.81\times t-------1

Range is given by

R=ut

where u=initial velocity

68=u\times t

t=\frac{68}{u}

substitute the value of t in eqn 1

v_y=9.81\times \frac{68}{u}

v_y\times u=9.81\times 68=667.08--------2

and tan(3)=\frac{v_y}{u}

v_y=utan(3)=0.0524u

substitute it in 2

0.0524 u^2=667.08

u^2=12,728.644

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6 0
4 years ago
WILL MARK BRAINLIEST PLEASE HELP AND SHOW ALL WORK
jok3333 [9.3K]

Answer:

Same reading.

Explanation:

Assume that after the string breaks the ball falls through the liquid with constant speed. If the mass of the bucket and the liquid is 1.20 kg, and the mass of the ball is 0.150 kg,

A.) Before the string break, the total weight = weight of the can + weight of the water.

According to Archimedes' Principle which state that: “A body immersed in a liquid loses weight by an amount equal to the weight of the liquid displaced.” Archimedes principle also states that: “When a body is immersed in a liquid, an upward thrust, equal to the weight of the liquid displaced, acts on it

B.) After the string break.

The scale will have the same reading as before the string break.

6 0
3 years ago
How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

5 0
3 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Tems11 [23]

Answer:

5.4 ms⁻¹

Explanation:

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L = length of the meter stick = 1 m

m = mass of the meter stick

w = angular speed of the meter stick as it hits the floor

v = speed of the other end of the stick

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I = Moment of inertia of the stick about one end

For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

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7 0
3 years ago
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