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kow [346]
3 years ago
7

Isla made a diagram to compare X-rays and radio waves.

Physics
1 answer:
pickupchik [31]3 years ago
6 0

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

Explanation:

Electromagnetic waves are waves consisting of oscillations of electric and magnetic field in a direction perpendicular to the direction of motion of the wave.

Electromagnetic waves travel at the speed of light (c=3.0\cdot 10^8 m/s) in a vacuum, and they are transverse in nature (the direction of vibration is perpendicular to the direction of propagation).

Electromagnetic waves are classified into different types according to their wavelength and frequency. In order from shortest to longest wavelength (and so, from highest to lowest frequency, since frequency is inversely proportional to the wavelength), we have:

Gamma rays

X-rays

Ultraviolet radiation

Visible light

Infrared radiation

Microwaves

Radio waves

Therefore, we can no says that:

X-rays: has a higher frequency than Radio waves

Radio waves: have a longer wavelength than x-rays

Both: they travel at the same speed

Therefore, the correct pairing is:

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

Learn more about electromagnetic waves:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

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What should you do if a fire breaks out in the back of your boat?
valkas [14]

If a fire breaks out in the back of your boat you should put the back of the boat into the wind so that the fire will not spread easily. Then turn off the engine and paddle the boat to keep the boat into the wind. Also use a fire extinguisher to put the fire off.

8 0
4 years ago
A football player, with a mass of 69.0 kg, slides on the ground after being knocked down. At the start of the slide, the player
White raven [17]

Answer:

(a) -472.305  J

(b) 1 m

Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by0.5mv^{2}

Initial kinetic energy is 0.5\times 69\times 3.7^{2}=472.305 J

Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305  J=-472.305  J

(b)

From fundamental kinematic equation

v^{2}=u^{2}+2as

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

s=\frac {v^{2}-u^{2}}{-2a} but a=\mu g hence

s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m

7 0
3 years ago
Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.99 J of work to set the ball spinnin
scoundrel [369]

To solve this problem it is necessary to apply the concepts related to rotational kinetic energy, the definition of the moment of inertia for a sphere and the obtaining of the radius through the circumference. Mathematically kinetic energy can be given as:

KE= I\omega^2

Where,

I = Moment of inertia

\omega = Angular velocity

According to the information given we have that the radius is

\Phi= 2\pi r

0.749m = 2\pi r

r = 0.1192m

With the radius obtained we can calculate the moment of inertia which is

I = \frac{2}{3}mr^2

I = \frac{2}{3}(0.624)(0.1192)^2

I = 5.91*10^{-3} kg \cdot m^2

Finally, from the energy equation and rearranging the expression to obtain the angular velocity we have to

\omega = \sqrt{\frac{2KE}{I}}

\omega = \sqrt{\frac{2(1.99)}{5.91*10^{-3}}}

\omega = 25.95rad/s

Therefore the angular speed will the ball rotate is 25.95rad/s

8 0
3 years ago
Please Help me!! (Kinetic and Potential Energy)​
katovenus [111]

Answer:

ur mom

Explanation:

4 0
3 years ago
A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped.
Elza [17]

Answer:

1000 N

Explanation:

First, we need to find the deceleration of the running back, which is given by:

a=\frac{v-u}{t}

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

a=\frac{0-5 m/s}{0.5 s}=-10 m/s^2

And now we can calculate the force exerted on the running back, by using Newton's second law:

F=ma=(100 kg)(-10 m/s^2)=-1000 N

so, the magnitude of the force is 1000 N.

6 0
3 years ago
Read 2 more answers
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