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Olegator [25]
3 years ago
6

A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei

ght (w) of the box?
73 N

36 N

79 N

86 N

62 N

Physics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

w = 73 N

Explanation:

Since the box is held by the ropes it means that the resulting tension is equal to the weight of the box

T_res = w

Now, the resulting tension is a combination of the tension of each rope.

Since we want to find the vertical component we must multiply by the cosine of 30 degrees the value of T

T_res =  T*cos(30) + T*cos(30)

T_res = 2*(42 N)*(0.866)

T_res = 72.746 N

T_res = w = 72.746 N

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<u>Explanation:</u>

To get the density of the material, the formula would be:

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To travel at constant speed, a car engine provides 24KW of useful power. The driving force on the car is 600N. At what speed doe
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Answer:

The speed traveled by the car is 40 meter per second.

Explanation:

The formula for the relation between the power and the force is as follows:

P = Fv

Where F is the force and v is the speed.

As given

To travel at constant speed, a car engine provides 24KW of useful power. The driving force on the car is 600N.

F = 600 N

Convert power from KW to W.

1 KW = 1000 W

24 KW = 24 × 1000 W

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Thus

P = 24000 W

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A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ
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Answer:

- 2.7 x 10^-6 J

Explanation:

q1 = 1 nC  at x = 0 cm

q2 = - 1 nC at x = 1 cm

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U=\frac{Kq_{1}q_{2}}{r}

where r be the distance between the two charges

By use of superposition principle, the total energy of the system is given by

U = U_{1,2}+U_{2,3}+U_{3,1}

U=\frac{Kq_{1}q_{2}}{0.01}+\frac{Kq_{2}q_{3}}{0.01}+\frac{Kq_{3}q_{1}}{0.02}

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U = - 2.7 x 10^-6 J

3 0
3 years ago
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