Match the following vocabulary words with the correct definitions.

If the enthalpy value for a reaction is negative, what does that indicate about the reaction?

likoan [24]

This indicates that the reaction is exothermic meaning that it releases heat/energy

7 0

3 years ago

Read 2 more answers

______ will have a higher entropy than 50.0 g CO2 (g) at 56 oC.

Tomtit [17]

1) The more mass is the more entropy , because there are more particles, there is disorder.
2) Than higher temperature --- the more entropy.
3) Gas has more disorder than liquid, so gas has more entropy.
So, correct answer is E.

5 0

3 years ago

Propane, C3H8, consists of ________________ bonds and it can be expected to dissolve in hexane and to not dissolve in water.

PtichkaEL [24]

Non-polar covalent

Explanation:

Propane is made up of non-polar covalent bonds and it can be expected to dissolve in hexane and to not dissolve in water.

Propane is an hydrocarbon gas.

It forms by sharing of electrons between two atoms with very low electronegativity differences.

This differences results in equal sharing of the shared electron. Therefore they form a non-polar covalent bond.

Water is a polar covalent compound and cannot dissolve compounds that are not polar like propane.

Propane will only dissolve in a like substance like hexane which is equally non-polar.

learn more:

Covalent compounds brainly.com/question/3109255

#learnwithBrainly

4 0

3 years ago

What is the density of a liquid that has a mass of 27g and a volume of 30mL?

NNADVOKAT [17]

Answer: 7 g/cm to the third power
Hope this helps
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-Carrie

8 0

3 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

4 years ago