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Vika [28.1K]
2 years ago
15

Match the following vocabulary words with the correct definitions.

Chemistry
1 answer:
son4ous [18]2 years ago
4 0

Answer:

1 mass

2 matter

3 weight

4 molecule

5 compound

6 atom

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A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak
worty [1.4K]

Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

  • n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol

<em>We use the reaction to calculate n₂</em>:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

  • mol CO₂:

0.1900 mol CO * \frac{2molCO_{2}}{2molCO} = 0.1900 mol CO₂

  • mol N₂:

0.1900 mol NO * \frac{1molN_{2}}{2molNO} = 0.095 mol N₂

  • n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

3 0
3 years ago
CAN SOMEONE HELP ME PLEASE . i have the definitions i just need help with examples
Alla [95]
Collision Coverage Example:
You're driving down the street and rear end the car in front of you. Your liability insurance will pau for the damage done to the other car, and your Collision insurance (or coverage) will pay for the damage done to your own vehicle because this was an accident in which you collided with another vehicle.

Comprehensive Coverage Example:
When there's damage to your windshield; damage from natural disasters and bad weather conditions, like wind storms, hurricanes, floods, earthquakes, hail, etc,.

Hope I helped!
6 0
3 years ago
Mass is usually measured using ?
Brut [27]
Balance
Usually it’s a triple beam balance.
A ruler measures length
8 0
2 years ago
How do cherries in a cherry tree help the plant reproduce
Harlamova29_29 [7]
Because if the cherries are eaten them the seeds/pit will be eaten as well which will be carried by whatever ate it and pooped out and can make more of its kind but it is different with wind and water do you also want that answer?
7 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
3 years ago
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