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3 years ago

Different types of cells

Chemistry

2 answers:

il63 [147K]3 years ago

8 0

Answer:

4 main types: Epithelial, nerve, muscle and connective tissue

Specifics: stem cells, red blood cells, white blood cells (neutrophils, eosinophils, basophils, lymphocytes), platelets, nerve cells, neuroglia cells, muscle cells (skeletal muscle cells, cardiac muscle cells, smooth muscle cells), cartilage cells, bone cells, skin cells, fat cells, sex cells

olga_2 [115]3 years ago

4 0

Answer:

Epithelial cells, Nerve cells, muscle cells, and connective tissue cells

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4 years ago

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Water is known as a polar molecule because Check all that apply. a. the oxygen and hydrogen atoms have the same electronegativit

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Answer:

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3 years ago

Sodium phosphate dissolves as follows: na3po4(s) → 3na (aq) po4-(aq). How many moles of na3po4 are required to make 1. 0 l of so

bezimeni [28]

The 0.05 moles of $Na_{3}PO_{4}$ required to make 1 L of solution in which the $Na$ concentration is 0. 15 M.

Calculation,

The Sodium phosphate dissolves as follows:

$Na_{3}PO_{4}(s)$ → $3Na^{+} (aq)+PO_{4}^{-} (aq)$

To make 1. L of solution in which the $Na^{+$ concentration is 0. 15 M

The morality of $Na^{+$ = 0.15 M = number of moles / volume in lit

The morality of $Na^{+$ = 0.15 M = number of moles /1 Lit

number of moles of $Na^{+$ = 0.15 mole

The mole ratio is 1: 3

It means, the 1 mole of $Na_{3}PO_{4}(s)$ required to form 3 mole of $Na^{+$

So, to form 0.15 mole of $Na^{+$ = 1×0.15 / 3 moles of $Na_{3}PO_{4}(s)$ required.

Hence, number of moles of $Na_{3}PO_{4}(s)$ required = 0.05 moles.

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2 years ago

Calculate the amount of CO2 (in kg) released when 1 kg of coal is burned. Assume that carbon content of the coal is 50% by mass.

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Answer:

1.8321 kg

Explanation:

The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is $\frac {50}{100}\times 1\ kg=0.5\ kg$

Also, 1 kg = 1000 g

So, mass of carbon = 500 g

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Molar mass of carbon = 12.0107 g/mol

Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles

Considering the reaction:

$C+O_2\rightarrow CO_2$

From the reaction,

1 mole of C react to form 1 mole of $CO_2$

So,

41.6295 moles of C react to form 41.6295 moles of $CO_2$

Moles of $CO_2$ = 41.6295 moles

Molar mass of $CO_2$ = 44.01 g/mol

So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g

Also, 1g = 0.001 kg

<u>So, amount of $CO_2$ released = 1.8321 kg</u>

4 0

3 years ago

Keeping the number of moles constant, what is the final pressure in atm if the temperature was cooled from -91.5°C to -239°C, th

34kurt

Answer:

P2 = 0.935 atm

Explanation:

initial conditions:

∴ V1 = 3.41 L

∴ T1 = - 91.5 °C + 273 = 181.5 K

∴ P1 = 3990 torr * ( atm / 760 torr ) = 5.25 atm

PV = RTn

∴ R = 0.082 atm.L / K.mol

⇒ n = P1V1 / RT1 = ((5.25 atm)*(3.41 L)) / ((0.082 atm.L/K.mol)*(181.5 K))

⇒ n = 1.107 mol

final conditions:

∴ V2 = 3.3 L

∴ T2 = - 239 °C = 34 K

∴ n = 1.107 mol

⇒ P2 = nRT2 / V2

⇒ P2 = ((1.107 mol)*(0.082 atm.L/K.mol)*(34 K)) / 3.3 L

⇒ P2 = 0.935 atm

3 0

3 years ago

Different types of cells​

Different types of cells