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Answer:
468 h
Explanation:
Let's consider the reduction of chromium (III) to chromium that occurs in the electrolytic purification.
Cr³⁺ + 3 e⁻ → Cr
We can establish the following relations.
- 1 kg = 1,000 g
- The molar mass of Cr is 52.00 g/mol
- 1 mole of Cr is deposited when 3 moles of electrons circulate
- The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
- 1 A = 1 c/s
- 1 h = 3,600 s
The hours that will take to plate 11.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 38.0 A is:
There isn't a most favorable equivalent resonance of the Sulfate ion because they are all identical in charge and there is no change in Electronegativity between the Oxygen atoms.
What is atom?
An atom is a particle of count that uniquely defines a chemical element. Atoms include a critical nucleus surrounded with the aid of using one or greater negatively charged electrons. The nucleus is undoubtedly charged and carries one or greater quite heavy debris referred to as protons and neutrons.
Therefore, There isn't a most favorable equivalent resonance of the Sulfate ion because they are all identical in charge and there is no change in Electronegativity between the Oxygen atoms.
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The density of the gas can be given by the mass of the substance and its volume. A 4084 gms of ammonia has a volume of 5.99 L.
<h3>What is STP?</h3>
STP is the condition at which the temperature and the pressure of the gas are at the normal and standard conditions.
The density of the ammonia = 681.9gm/L
The mass = 4084 gm
The volume is calculated as:
V = Mass ÷ Volume
= 4084 ÷ 681.9
= 5.99 L
Therefore, at STP the volume of ammonia is 5.99 L.
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Answer:
13.301
Explanation:
To calculate the pH of the solution, we must obtain the pOH of the solution as illustrated below:
The dissociation equation is given below
Ba(OH)2 <==> Ba^2+ + 2OH^-
Since Ba(OH)2 dissociate to produce 2moles of OH^-, the concentration of OH^- = 2x0.1 = 0.2M
pOH = - Log[OH^-]
pOH = - Log 0.2
pOH = 0.699
But
pH + pOH = 14
pH = 14 — pOH
pH = 14 — 0.699
pH = 13.301
