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lana66690 [7]
2 years ago
8

Different types of cells​

Chemistry
2 answers:
il63 [147K]2 years ago
8 0

Answer:

4 main types: Epithelial, nerve, muscle and connective tissue

Specifics: stem cells, red blood cells, white blood cells (neutrophils, eosinophils, basophils, lymphocytes), platelets, nerve cells, neuroglia cells, muscle cells (skeletal muscle cells, cardiac muscle cells, smooth muscle cells), cartilage cells, bone cells, skin cells, fat cells, sex cells

olga_2 [115]2 years ago
4 0

Answer:

Epithelial cells, Nerve cells, muscle cells, and connective tissue cells

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Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration (M)initial:change:equilibrium:[XY]0.2
Allushta [10]

This is an incomplete question, here is a complete question.

Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse.

The chemical reaction is:

XY(g)\rightleftharpoons X(g)+Y(g)

Concentration(M)        [XY]            [X]            [Y]

(M)initial:                     0.200        0.300      0.300

change:                         +x               -x              -x

equilibrium:             0.200+x      0.300-x     0.300-x

The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Based on a Kc value of 0.140 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively?

Answer : The Equilibrium concentrations of XY, X, and Y is, 0.104 M, 0.204 M and 0.204 M respectively.

Explanation :

The chemical reaction is:

                                 XY(g)\rightleftharpoons X(g)+Y(g)

initial:                      0.200      0.300   0.300

change:                    +x             -x           -x

equilibrium:      (0.200+x)  (0.300-x)   (0.300-x)

The equilibrium constant expression will be:

K_c=\farc{[X][Y]}{[XY]}

Now put all the given values in this expression, we get:

0.140=\frac{(0.300-x)\times (0.300-x)}{(0.200+x)}

By solving the term 'x', we get:

x = 0.0963 and x = 0.644

We are neglecting the value of x = 0.644 because the equilibrium concentration can not be more than initial concentration.

Thus, the value of x = 0.0963

Equilibrium concentrations of XY = 0.200+x = 0.200+0.0963 = 0.104 M

Equilibrium concentrations of X = 0.300-x = 0.300-0.0963 = 0.204 M

Equilibrium concentrations of X = 0.300-x = 0.300-0.0963 = 0.204 M

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3 years ago
Electric lights will not come on unless their electrical circuit is a?
nordsb [41]

Answer:

closed circuit

Explanation:

Hope this helps- Good luck! ^w

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2 years ago
calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure
andriy [413]

Answer:

5.5 L

Explanation:

First we <u>convert 10 g of propane gas</u> (C₃H₈) to moles, using its <em>molar mass</em>:

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Then we <u>use the PV=nRT formula</u>, where:

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  • V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

  • V = 5.5 L
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Answer:

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Explanation:

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