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Olin [163]
3 years ago
15

(ii) Arrange the following metals in decreasing order of their reactivity:Fe, Zn, Na, Cu, Ag​

Chemistry
1 answer:
ratelena [41]3 years ago
4 0

Answer:

Given Elements are

  • Ferrus(Fe)
  • Zinc(Zinc)
  • Sodium (Na)
  • Copper (Cu)
  • Silver(Ag)
<h3>Decreasing Order:-</h3>

Na>Zn>Fe>Cu>Ag

<h3><u>Expla</u><u>nation</u><u>:</u><u>-</u></h3>
  • Here is the reactivity series of elements to let you understand better .

\setlength{\unitlength}{0.8 cm}\begin{picture}(20,15)\thicklines\put(5,9.5){\large {\boxed{ \sf{Reactivity \:  series}}}}\put(0.8,8){\large\sf K \qquad\qquad\qquad Potassium\qquad\qquad\qquad \: maximum}\put(0.8,7.2){\large\sf Na \qquad\qquad\qquad Sodium\qquad\qquad\qquad\quad \: reactivity}\put(0.8,6.2){\large\sf Ca\qquad\qquad\qquad \: Calcium}\put(0.8,5.2){\large\sf Mg\qquad\qquad\quad \: Magnesium}\put(0.8,4.2){\large\sf Al\qquad\qquad\qquad \: Aluminium\qquad\qquad\qquad \: decreasing}\put(0.8,3.2){\large\sf Zn\qquad\qquad\quad\qquad \: Zinc\qquad\qquad\qquad\qquad \:reactivity}\put(0.8,2.2){\large\sf Fe\qquad\qquad\quad\qquad Ferrous}\put(0.8,1.2){\large\sf Pb\qquad\qquad\qquad \: \:\: Lead}\put(0.8,0.2){\large\sf H\qquad\qquad\qquad \:  \:Hydrogen}\put(0.8, - 0.6){\large\sf Cu\qquad\qquad\qquad \: Copper}\put(0.8, - 1.5){\large\sf Hg\qquad\qquad\qquad \: Mercury}\put(0.8, - 2.5){\large\sf Ag\qquad\qquad\qquad \: \:Silver}\put(0.8, - 3.5){\large\sf Au\qquad\qquad\qquad \: \:  Gold\qquad\qquad\qquad\quad \:  \: minimum reactivity}\put(9.3,8.2){\vector(0, - 2){12}}\end{picture}

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For each balanced reaction, indicate the total number of atoms in the table below.
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(i) Make ammonia number of atoms on reactant side is 8 and on product side is 8. (ii) Separate water number of atoms on reactant side is 6 and on product side is 6. (iii) Combust methane number of atoms on reactant side is 9 and number of atoms on product side is 9.  

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

(i) Make Ammonia

First we have to write the balanced chemical equation

             N₂ + 3H₂ → 2NH₃

Reactant side              Product side

N = 2                             N = 2

H = 6                             H = 6

So total number of atoms on product and reactant side is 8.

(ii) Separate Water

First we have to write the balanced chemical equation

            2H₂O → 2H₂ + O₂

Reactant side              Product side

H = 4                             H = 4

O = 2                             O = 2

So total number of atoms on product and reactant side is 6.

(iii) Combust methane

First we have to write the balanced chemical equation

       CH₄ + 2O₂ → 2H₂O + CO₂

Reactant side              Product side

C = 1                             C = 1

H = 4                            H = 4

O = 4                            O = 4

So total number of atoms on product and reactant side is 9.

Thus from the above conclusion we can say that For each balanced reaction, the total number of atoms are

Reaction                            Total number of atoms

                                     Reactant side           Product side

Make Ammonia                   8                               8

Separate Water                   6                               6

Combust Methane              9                               9

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: For each balanced reaction, indicate the total number of atoms in the table below.

Reaction                            Total number of atoms

                                     Reactant side           Product side

Make Ammonia            _________              __________

Separate Water            _________              __________

Combust Methane       _________              __________

3 0
2 years ago
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