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neonofarm [45]
3 years ago
13

Astronomers observe a spectral analysis of a distant star where a particular element has a spectral line with a wavelength of 66

3 nm. In the laboratory, the same element has a spectral line with a wavelength of 645 nm.
a. How fast is the star moving, and in what direction is it moving?

b. The same element on Earth’s surface is observed from a space shuttle orbiting at 7800 m/s,
350 km above Earth. Is the same shift in the spectral line seen from the space shuttle? Why or why not?
Physics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

(a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

Explanation:

Given that,

Wavelength of spectral line = 663 nm

Wavelength of spectral line in lab = 645 nm

(a). We need to calculate the velocity

Using doppler's effect

\Delta \lambda=\dfrac{v}{c}\lambda

Where, \Delta\lambda= change in wavelength

v = velocity

c = speed of light

Put the value into the formula

663-645=\dfrac{v}{3\times10^{8}}\times663

v=\dfrac{3\times10^{8}(663-645)}{663}

v=8144796.38\ m/s

v=8.1\times10^{6}\ m/s

The direction of star toward the earth.

(b). Speed = 7800 m/s

We need to calculate the shift

Using formula of shift

\Delta \lambda=\lambda(\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}-1)

Put the value into the formula

\Delta \lambda=645\times(\sqrt{\dfrac{1+\dfrac{7800}{3\times10^{8}}}{1-\dfrac{7800}{3\times10^{8}}}}-1)

\Delta\lambda=0.0168\ nm

This shift is small compare to the the movement of Earth around the sun.

Hence, (a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

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Neutrons and protons are located in the nucleus of the atom.

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And electrons are in the electron cloud.

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The North Star, or Polaris, is the brightest star in the constellation Ursa Minor, the little bear (also known as the Little Dipper). As viewed by observers in the Northern Hemisphere, Polaris occupies a special place
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The internal energy of material is determined by
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The combined amount of kinetic and potential energy of its molecules
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Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
3 years ago
Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 7.1 W. While
Gnom [1K]

Answer:

A) R = 190.42 Ω

B) P = 5.325 W

Explanation:

We are given;

Total power;P_tot = 7.1 W

Voltage;V = 26 V

A)We are told that while the battery is still connected, one of the resistors is heated, so that its resistance doubles.

Thus, the power is doubled.

Now, formula for power is;

P = IV

Thus, since power is doubled, we have;

P = 2(IV)

Now, formula for current is; I = V/R

So, P = 2V²/R

Making R the subject, we have;

R = 2V²/P

In this question, P is p_total = 7.1 W

Thus;

R = (2 × 26²)/7.1

R = 190.42 Ω

B) Now, the resistance of the resistors are R and 2R.

Formula for power in this context is;

P = V²/R

Thus,

Total power delivered to the resistors is;

P = V²/R + V²/2R

P = 3V²/2R

P = (3 × 26²)/(2 × 190.42)

P = 5.325 W

8 0
3 years ago
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