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il63 [147K]
4 years ago
7

Question 4,5,and 6 Plz

Physics
1 answer:
borishaifa [10]4 years ago
4 0

Answer:

4.) At room temperature, it changes directly from a solid to a gas a process called sublimation. This expansion causes a rapid temperature drop, and some of the carbon dioxide freezes into solid pellets of dry ice.

5.) Balsa wood combines the two elements necessary to a successful flight: strength and lightness. Balsa wood is also easy to cut and carve with just a good, sharp hobby knife or razor saw, so no need for heavy power tools. Or any lighter wood.

6.) Density is mass/volume. So: D=10.7/5

D=2.17g/cm^3

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If a 60 kg woman, runs up a flight of stairs having a total rise of 4.0m in a time of 4.2s. What average power did she supply?
LenKa [72]
 <span>PE = m * g * h 
PE = 60 * 9.8 * 4 
PE = 2352 J 

Power = E/t 

Power = PE/t 
Power = 2352/4.2 
Power = 560 Watt</span>
6 0
4 years ago
Which one of the following is a decomposition reaction?
frutty [35]
(a) is a decomposition reaction
4 0
4 years ago
The world’s supply of fossil fuels will _____.
Mekhanik [1.2K]

The world’s supply of fossil fuels will dwindle slowly until a replacement source is found that provides the same power.

bc some day we will actually run out of it and find sth that gives power

3 0
3 years ago
Read 2 more answers
What was his average swimming speed during the second half of the race if he tied the record, which was at an average speed of 2
Nimfa-mama [501]

<span>I believe this question has additional detail which stated that during the 1st half, his speed was 2.01 m/s. From this we can calculate his speed during the second half, v2, using the formula:</span>

v_ave = (v1 + v2) / 2

2.05 m/s = (2.01 m/s + v2) / 2

<span>v2 = 2.09 m/s</span>

4 0
3 years ago
Determine the ratio of Earth's gravitational force exerted on an 80-kg person when at Earth's surface and when 1400 km above Ear
postnew [5]

m = mass of the person = 80 kg

M = mass of earth = 5.98 x 10²⁴ kg

R = radius of earth = 6.37 x 10⁶ m

h = height above the earth's surface = 1400 km = 1.4 x 10⁶ m

r₁ = initial distance of the person from the center of earth when on surface = R =  6.37 x 10⁶ m

r₂ = final distance of the person from the center of earth when at some height = R + h =  6.37 x 10⁶ + 1.4 x 10⁶ = 7.77 x 10⁶ m


F₁ = Gravitational force of earth on the person when at surface

Gravitational force of earth on the person when at surface is given as

F₁ = G M m/r₁²                                             eq-1

F₂ = Gravitational force of earth on the person when at some height

Gravitational force of earth on the person when at some height is given as

F₂ = G M m/r₂²                                             eq-2

dividing eq-1 by eq-2

F₁ /F₂ = (G M m/r₁² )/(G M m/r₂²)

F₁ /F₂ = r₂²/r₁²

inserting the values

F₁ /F₂ = (7.77 x 10⁶)²/(6.37 x 10⁶)²

F₁ /F₂ = 1.49

3 0
4 years ago
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