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Fantom [35]
10 months ago
12

Help pls it’s about physics I need all of them

Physics
1 answer:
damaskus [11]10 months ago
4 0

1) Amy runs 2 miles south, then takes a turn and runs 3 miles north the displacement is 1 mile North.

2) Distance is 800m and Displacement will be zero.

3) Distance is 90 feet, and Displacement is 30 feet.

4) Distance is 4 miles and Displacement is 0.

Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion."

The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International System of Units (SI) (m). Usually, displacement is defined or measured along a straight line.

1) Here, the person goes 2 miles south and then 3 miles north.

3-2 = 1 mile north

So, Displacement is 1 mile North.

2) It is given that Jermaine runs 2 laps around the track.

The perimeter of the track on which he runs = 400m

Here as it is given laps, which means the track is circular in shape.

Distance covered in 1 lap

So total distance covered in 2 laps= 2 × 400 = 800 m

Displacement will be zero as the initial and the final position is the same. So, no positional change happens.

To know more about Displacement refer to:  brainly.com/question/2109763

#SPJ9

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shepuryov [24]

Answer:

Explanation:

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sin ( 90 - 25 ) / sinr = μ , μ is the refractive index of the tube , r is angle of refraction in the medium of tube

r = 90 - C where C is critical angle between μ and body medium in which tube will be inserted.

sin ( 90 - 25 ) / sin( 90 - C)  = μ

sin65 / cos C = μ

sinC = 1.33 / μ  , where 1.33 is the refractive index of body liquid.

From these equations

sin65 / cos C = 1.33 / sinC

TanC = 1.33 / sin65

TanC = 1.33 / .9063

TanC = 1.4675

C= 56°

sinC = 1.33 / μ

μ = 1.33 / sinC

= 1.33 / sin56

= 1.33 / .829

μ = 1.6   Ans

3 0
2 years ago
Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
kifflom [539]
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6 0
3 years ago
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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.
amm1812

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

8 0
3 years ago
An electric grinder uses a grinding wheel
luda_lava [24]
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<span>(B) </span>
<span>(1/2)(8.33 rev/s²)(3.0 s)² = 37.5 rev </span>

<span>(C) </span>
<span>(1500 rev/min)(min / 60 s)[2π(0.12 m) / rev] = 18.8 m/s</span>
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