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Fantom [35]
1 year ago
12

Help pls it’s about physics I need all of them

Physics
1 answer:
damaskus [11]1 year ago
4 0

1) Amy runs 2 miles south, then takes a turn and runs 3 miles north the displacement is 1 mile North.

2) Distance is 800m and Displacement will be zero.

3) Distance is 90 feet, and Displacement is 30 feet.

4) Distance is 4 miles and Displacement is 0.

Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion."

The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International System of Units (SI) (m). Usually, displacement is defined or measured along a straight line.

1) Here, the person goes 2 miles south and then 3 miles north.

3-2 = 1 mile north

So, Displacement is 1 mile North.

2) It is given that Jermaine runs 2 laps around the track.

The perimeter of the track on which he runs = 400m

Here as it is given laps, which means the track is circular in shape.

Distance covered in 1 lap

So total distance covered in 2 laps= 2 × 400 = 800 m

Displacement will be zero as the initial and the final position is the same. So, no positional change happens.

To know more about Displacement refer to:  brainly.com/question/2109763

#SPJ9

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A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to
geniusboy [140]

Answer:

4.3 km

Explanation:

5 0
2 years ago
In a hydroelectric power plant, 65 m3 /s of water flows from an elevation of 90-m to a turbine-generator, where electricity is g
Mariulka [41]

The electric output of the plant is 48.19 MW

First we need to calculate the water power, it is given by the formula

WP=ρQgh

Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head

Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW

Now the overall efficiency of the hydroelectric power plant is given as

η=\frac{electric power}{water power}

Plugging the values in the above equation

0.84=EP/57.38

EP=48.19 MW

Therefore, the electric output of the plant is 48.19 MW.

3 0
3 years ago
1.Mention two uses of the concave mirror.
Anuta_ua [19.1K]

Answer:

1. telescope

2.

f =  \frac{r}{2}

f =  \frac{r}{2}f- focal length

f =  \frac{r}{2}f- focal length r- the radius of curvature of the mirror

\frac{1}{f}  =   \frac{1}{p}  +  \frac{1}{l}

p-the distance of the object from the vertex of the mirror

l-the distance of the figure from the vertex of the mirror

8 0
3 years ago
A 2200 kilogram car is accelerating at 3.4 m/s/s. what is the NET force?
sdas [7]
We Know, F = m*a
F = 2200 * 3.4
F = 7480 Kg m/s²

So, your final answer is 7480
7 0
3 years ago
Three point charges are arranged on a line. Charge q3 = 5 nC and is at the origin. Charge q2 = - 3 nC and is at x = 4 cm. Charge
Taya2010 [7]

Answer:

q₁ = + 1.25 nC

Explanation:

Theory of electrical forces

Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.

Known data

q₃=5 nC

q₂=- 3 nC

d₁₃=  2 cm

d₂₃ = 4 cm

Graphic attached

The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.

For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So,  the charge q₁ must be positive(q₁+).

The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).

The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs.  F₂₃ is directed to the right (+x)

Calculation of q1

F₁₃ = F₂₃

\frac{k*q_{1}*q_3 }{(d_{13})^{2}  } = \frac{k*q_{2}*q_3 }{(d_{23})^{2}  }

We divide by (k * q3) on both sides of the equation

\frac{q_{1} }{(d_{13})^{2} } = \frac{q_{2} }{(d_{23})^{2} }

q_{1} = \frac{q_{2}*(d_{13})^{2}   }{(d_{23} )^{2}  }

q_{1} = \frac{5*(2)^{2} }{(4 )^{2}  }

q₁ = + 1.25 nC

3 0
3 years ago
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