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Fantom [35]
1 year ago
12

Help pls it’s about physics I need all of them

Physics
1 answer:
damaskus [11]1 year ago
4 0

1) Amy runs 2 miles south, then takes a turn and runs 3 miles north the displacement is 1 mile North.

2) Distance is 800m and Displacement will be zero.

3) Distance is 90 feet, and Displacement is 30 feet.

4) Distance is 4 miles and Displacement is 0.

Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion."

The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International System of Units (SI) (m). Usually, displacement is defined or measured along a straight line.

1) Here, the person goes 2 miles south and then 3 miles north.

3-2 = 1 mile north

So, Displacement is 1 mile North.

2) It is given that Jermaine runs 2 laps around the track.

The perimeter of the track on which he runs = 400m

Here as it is given laps, which means the track is circular in shape.

Distance covered in 1 lap

So total distance covered in 2 laps= 2 × 400 = 800 m

Displacement will be zero as the initial and the final position is the same. So, no positional change happens.

To know more about Displacement refer to:  brainly.com/question/2109763

#SPJ9

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3 years ago
You pick up a 10-newton book off the floor and put it on a shelf 2 meters high. How much work did you do?​
Murljashka [212]

Answer:

20 J

Explanation:

Given:

Weight of the book is, W=10\ N

Height or displacement of the book is, d=2\ m

The work done on the book to raise it to a height of 2 m on a shelf is against gravity. The gravitational force acting on the book is equal to its weight. Now, in order to raise it, an equal amount of force must be applied in the opposite direction.

So, the force applied by me should be equal to weight of the body and in the upward direction. The displacement is also in the upward direction.

Now, work done by the applied force is equal to the product of force applied and displacement of book in the direction of the applied force.

Therefore, work done is given as:

Work=W\times d\\Work=10\times 2=20\ J

Therefore, the work done to raise a book to a height 2 m from the floor is 20 J.

3 0
3 years ago
Read 2 more answers
Use the circuit diagram to decide if the lightbulb will light. Justify your answer.
podryga [215]

Answer:

The lightbulb will NOT light.

Explanation:

You put me in a difficult position.  I can't help it, but the "sample answer" is by far the best way to explain this, briefly and correctly.  There's no other choice but to copy it.

This is a short circuit. The branch without the bulb has almost no resistance, so all the current will flow through that branch instead of flowing through the bulb.

<em>If</em> the lower switch were <u>opened</u>, THEN we would have a series circuit.  Current would no longer have any other choice but to flow through the bulb, and the bulb would light.

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For a snowboard jumper in the air, what force or forces will be most important for modeling the motion?
Reptile [31]

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Explanation:

For a snowboard jumper in the air, two forces would be acting. One in the downward direction- the gravitational pull and second in the opposite direction to the motion, the drag force due to air. If the snowboard jumper jumps in the air at a certain angle with the horizontal. The forces are written as the sum of vertical and horizontal components. Hence, for the modeling the motion, gravitational force and drag force are important,

4 0
3 years ago
Two coils close to each other have a mutual inductance of 32 mH. If the current in one coil decays according to I=I0e−αt, where
fiasKO [112]

The emf induced in the second coil is given by:

V = -M(di/dt)

V = emf, M = mutual indutance, di/dt = change of current in the first coil over time

The current in the first coil is given by:

i = i₀e^{-at}

i₀ = 5.0A, a = 2.0×10³s⁻¹

i = 5.0e^(-2.0×10³t)

Calculate di/dt by differentiating i with respect to t.

di/dt = -1.0×10⁴e^(-2.0×10³t)

Calculate a general formula for V. Givens:

M = 32×10⁻³H, di/dt = -1.0×10⁴e^(-2.0×10³t)

Plug in and solve for V:

V = -32×10⁻³(-1.0×10⁴e^(-2.0×10³t))

V = 320e^(-2.0×10³t)

We want to find the induced emf right after the current starts to decay. Plug in t = 0s:

V = 320e^(-2.0×10³(0))

V = 320e^0

V = 320 volts

We want to find the induced emf at t = 1.0×10⁻³s:

V = 320e^(-2.0×10³(1.0×10⁻³))

V = 43 volts

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