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3241004551 [841]
3 years ago
5

How can liquid pressure phenomena be used in daily life. Give one example with explanation of working​?

Physics
1 answer:
N76 [4]3 years ago
8 0

Answer:

An example in which liquid pressure phenomena can be used in daily life is in Water blasting

Explanation:

Water blasting refers application of pressurized water to remove materials from the surface of objects.

There are different varieties of water blasting, including;

Hydrocleaning; Cleaning enabled by the use of high pressure water

Hydrodemolition; Demolition or removal of concrete using pressurized water

Hydrojetting; The spraying of water under pressure on surfaces in order to remove surface contaminants.

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A satellite orbiting Earth has a tangential velocity of 5000 m/s. Earth’s mass is 6 × 1024 kg and its radius is 6.4 × 106 m.
Aloiza [94]
When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.

Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration

\frac{ M_{E}*G }{  ( r_{E} )^{2}  } =ω^2r

where

M_{E} = mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>r_{E} = radius of earth
ω = angular velocity
<span>r = radius of orbit

To convert to angular velocity:

</span>Tangential velocity = rω
ω = 5000/r

Then,

\frac{ (6 \ x \  10^{24}) *(6.6742 \ x \ 10^{-11} ) }{ ( 6.4 \ x \  10^{6})^{2} }= ( \frac{5000}{r} )^{2} r

r = 2557110.465 m

Therefore, the distance of the centers of the earth and the satellite is 2.6 x 10^6 m.
<span>
</span>
4 0
3 years ago
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Consider a human population that consumes a certain resource. Which of the following statements about this situation is most lik
Papessa [141]
If the size of the population increases, the amount of the resource consumed will also increase
3 0
3 years ago
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11. How many millimeters are in 4.511 meters?
Snezhnost [94]

Answer:

4511millimetres

Explanation:

:>

6 0
4 years ago
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A diffraction grating is to be used to find the wavelength of the emission spectrum of a gas. The grating spacing is not known,
Bumek [7]

Answer:

528.9 nm

Explanation:

For a grating dsinθ = mλ where m = order of grating, d = grating space, λ = wavelength of light and θ = angle of deflection of light

First, we find the grating space d = mλ/sinθ where m = 2 for second order, λ = 632.8 nm = 632.8 × 10⁻⁹ m, θ = 43.2°

d = mλ/sinθ = 2 × 632.8 × 10⁻⁹ m ÷ sin43.2° = 1.849 × 10⁻⁶ m = 1.849 μm

We now find the wavelength of the light to be measured from λ = dsinθ/m

Here, θ = 34.9° and m = 2 for second order. So, we have

λ = dsinθ/m = 1.849 × 10⁻⁶ m × sin34.9° ÷ 2 = 0.5289 × 10⁻⁶ m = 528.9 nm

7 0
3 years ago
Consider three vectors A⃗ ,B⃗ and C⃗ all lying in the xy plane. Vector A⃗ has length 6.2 and makes an angle of 131 degrees with
vagabundo [1.1K]

Answer:

A) 2.09

B) -62.09°

Explanation:

If D = A+B+C  then C = D - A - B

Converting both A and B to rectangular coordinates, we get:

A = [-4.07 , 4.68]    and    B = [6.19 , 3.87]

Replacing these values we can get the x and y components of C:

C = [0.98 , -1.85]

Its module is:

|C| = \sqrt{0.98^2+(-1.85)^2}=2.09

Its angle is:

\alpha _c = atan(-1.85/0.98) = -62.09\°

8 0
3 years ago
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