When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.
Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration

ω^2r
where

= mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>

= radius of earth
ω = angular velocity
<span>r = radius of orbit
To convert to angular velocity:
</span>Tangential velocity = rω
ω = 5000/r
Then,

r = 2557110.465 m
Therefore, the distance of the centers of the earth and the satellite is
2.6 x 10^6 m.
<span>
</span>
If the size of the population increases, the amount of the resource consumed will also increase
Answer:
528.9 nm
Explanation:
For a grating dsinθ = mλ where m = order of grating, d = grating space, λ = wavelength of light and θ = angle of deflection of light
First, we find the grating space d = mλ/sinθ where m = 2 for second order, λ = 632.8 nm = 632.8 × 10⁻⁹ m, θ = 43.2°
d = mλ/sinθ = 2 × 632.8 × 10⁻⁹ m ÷ sin43.2° = 1.849 × 10⁻⁶ m = 1.849 μm
We now find the wavelength of the light to be measured from λ = dsinθ/m
Here, θ = 34.9° and m = 2 for second order. So, we have
λ = dsinθ/m = 1.849 × 10⁻⁶ m × sin34.9° ÷ 2 = 0.5289 × 10⁻⁶ m = 528.9 nm
Answer:
A) 2.09
B) -62.09°
Explanation:
If D = A+B+C then C = D - A - B
Converting both A and B to rectangular coordinates, we get:
A = [-4.07 , 4.68] and B = [6.19 , 3.87]
Replacing these values we can get the x and y components of C:
C = [0.98 , -1.85]
Its module is:

Its angle is:
