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3 years ago

Which of the following is not a solution? Saltwater Steel Vinegar Milk

Chemistry

1 answer:

atroni [7]3 years ago

6 0

I think it is steel because all other things are mixture of solutes or solvents

hope it is right!

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Question 3

igomit [66]

Answer:

1.04 moles

Explanation:

1 mole of MgF2 = 62.301

65.0÷62.301=1.04

4 0

3 years ago

Penn State Civil and Environmental Engineering Department just built a super-duper coal-fired power plant in Altoona, PA. It is

Travka [436]

Answer:

Part -A:

Sulfur released is $1.338 \times 10^{4}pounds/hour$ .

Part-B:

$SO_{2}$ released of per EPA norms is $4.865 /times 10^{-3}P/kw$ .

Explanation:

From the given,

The output = 1100 Mw

Efficiency = η = 0.4

Substitute the values in the following

Input = Output / η

$= \frac{1100}{0.4}= 2750 Mw$

Let's converts between joules to BTU.

1 BTU = 1056 J

Part-A;

$Energy\,\, required = Power \times time$

$2750 \times 10^{6} \,\, J/s \times 3600s = 9.9 \times 10^{12}J$

$Energy \,\, required = \frac{9.9 \times 10^{22}}{1056}= 9.375 \times 10^{9} BTU$

$Mass\,of\, coal\,required = \frac{9.375 \times 10^{9}}{14,000}=6.69 \times 10^{5}pounds$

But it has 2% sulfur

The mass of sulfur released

$6.69 \times 10^{5}pounds \,coal \times 0.02 = 1.338 \times 10^{4}pound$

Therefore, released sulfur is $1.338 \times 10^{4}pounds/hour$ .

Part -B;

One pound of sulfur produce two pounds of sulfur dioxide

Initial amount of produced sulfur =

$2 \times 1.338 \times 10^{4}pound = 2.676\times 10^{4}pound/hour$

Assuming we added a 80% efficiency then,

Released sulfur dioxide = $(1-0.8) \times SO_{2} \,produced =0.2 \times 2.676 \times 10^{4}Pounds/hr= 5.352 \times 10^{3}Pounds/hr$

Energy produced in an hour = $400 mw \times 1 hr = 1.1 \times 10^{6}kwh$

$SO_{2}\,released \, as \, per EPA = \frac{5.352 \times 10^{3} \,pounds}{1.1 \times 10^{6}kwh}= 4.865 \times 10^{-3}p\kwh$

Therefore, $SO_{2}$ released of per EPA norms is $4.865 /times 10^{-3}P/kw$ .

8 0

3 years ago

What would be the resulting molaritybof a solution made by dissolving 17.8 g of LiF in enough water to make a 915-millimeter sol

Sati [7]

Answer: Molarity of solution is 0.751 M. 

Reason:
Given: weight of solute (LiF) = 17.8 g, volume of solution = 915 ml = 0.915 l

We know that,
Molarity = $\frac{\text{weight of solute (g)}}{\text{Molecular weight X Volume of solution(l)}}$ 

Molecular Weight of LiF = 25.9 g/mol. 

∴, Molarity = $\frac{17.8}{25.9X0.915}$
 = 0.751 M

6 0

3 years ago

Read 2 more answers

Make a concept map using words below

jok3333 [9.3K]

WHat's a concept map again?

I forgot...

7 0

3 years ago

A lead mass is heated and placed in a foam cup caloriemeter containing 40.0mL of water at 17.0 C. The water reaches a temperatur

Mrrafil [7]

the Answer is 502 Joules

8 0

3 years ago