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Elan Coil [88]
3 years ago
9

Please help!!!!!!!!!!!!!!!

Chemistry
1 answer:
svlad2 [7]3 years ago
3 0
The 2nd one is the right answer

Hope this helped
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A mineral is scratched by apatite but not by calcite what could it’s hardness value be
mojhsa [17]

Answer:

hi!

Explanation:

The Mohs Hardness Scale ranks the order of hardness of minerals and some common objects. For example, your fingernail can scratch the minerals talc and gypsum, with a hardness of 2 or lower. A copper penny can scratch calcite, gypsum, and talc.

One of the most important tests for identifying mineral specimens is the Mohs Hardness Test.  

This test compares the resistance of a mineral to being scratched by ten reference minerals known as the Mohs Hardness Scale (see table at left).  

The test is useful because most specimens of a given mineral are very close to the same hardness. This makes hardness a reliable diagnostic property for most minerals.

"Hardness" is the resistance of a material to being scratched. The test is conducted by placing a sharp point of one specimen on an unmarked surface of another specimen and attempting to produce a scratch.  

5 0
3 years ago
Read 2 more answers
Amobarbital sodium react with ethanolic sodium hyrooxide
CaHeK987 [17]

Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.

<h3>What is the mechanism of amobarbital?</h3>

Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.

Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.

So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.

Learn more about Amobarbital here: brainly.com/question/7237163

#SPJ1

6 0
2 years ago
It took 70 seconds for 280cm³ of nitrogen to diffuse through a membrane. If Carbon(IV)Oxide is allowed to diffuse through the sa
Romashka-Z-Leto [24]

Answer:

t = 125.3 seconds

Explanation:

Molar mass of CO2 = 12+2(16) = 66

Molar mass of N2 = 2(14)= 28

rate of diffusion of N2 = volume/ time = 280cm³/70s

= 4cm³/s

let rate of CO2 = rate of diffusion of CO2 = volume/time

= 400/t

Using Graham's law of diffusion,

rN2/rCO2 = √M(CO2)/M(N2)

4/400/t =√44/28 = 4t/400= √11/7

t/100 = 1.253 , t= (100)(1.253)

t = 125.3 seconds

hence it takes CO2 125.3 seconds to diffuse through the membrane

5 0
3 years ago
Each element possesses unique chemical and physical properties. true or false
g100num [7]
True. An element's properties are based on their atomic numbers, atomic masses and electron configurations.


Hope it helped!
8 0
3 years ago
A 3.0-mol sample of kclo3 was decomposed according to the equation 2kclo3(s) --&gt; 2kcl(s) + 3o2(g) how many moles of o2 are fo
d1i1m1o1n [39]
2moles of O2 are formed.
5 0
3 years ago
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