Answer:
In the kinetic molecular theory, the molecules of an ideal gas are in constant random motion inside the container of the gas, and the pressure of the gas (which is the pressure exerted by the molecules in their collisions with the walls of the container) arise from this random motion of the molecules.
The main assumptions of the kinetic theory of gases are:
- The gas consists of a large number of molecules that collide between each other and the walls of the container; all these collisions are elastic
- The duration of the collisions is negligible compared to the time between the collisions
- The number of molecules is so large that statistics can be applied
- Intermolecular forces between the molecules are negligible (except during the collisions)
- The volume of the molecules is negligible compared to the volume of the container
In particular, the pressure of the gas is directly proportional to the average kinetic energy of the molecules, according to the equation:

where
p is the pressure of the gas
V is the volume of the container
K is the average kinetic energy of the molecules in the gas
We see that as the pressure is higher, the higher the kinetic energy of the particles: this means that the molecules will move faster, on average.
Therefore in this problem, the gas that exerts a pressure of 1.5 atm will have molecules moving faster than the molecules of the gas exerting a pressure of only 1.0 atm.
Answer:
it will be troubled and won't have peace
<span>Omitting this substance will not affect the appearance of hand lotion because it is a white or off white color. Since it is an alcohol compound if it is left out of the formula it will keep your hands from drying out as fast. </span>Triethanolamine is considered as an amine alcohol. The compound itself does not affect much the appearance of the hand lotion prepared as it is colorless, But, the alcohol If avoided would result in a hand lotion which would not get dried out easily
<u>Answer:</u> The solubility of ethylene gas in water is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,
= Henry's constant = 
= molar solubility of ethylene gas = ?
= partial pressure of ethylene gas = 0.684 atm
Putting values in above equation, we get:

Converting this into grams per liter, by multiplying with the molar mass of ethylene:
Molar mass of ethylene gas = 28 g/mol
So, 
Hence, the solubility of ethylene gas in water is 