Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
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To find:
The 
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Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]
Using the angle sum property in triangle AOB, we get
Hence, the measure of angle AOB is 120 degrees.
Given is a parallelogram whose base is b = 10 inches and it says height is 2 more than half-value of base i.e. h = 2 + (b ÷ 2).
So height is h = 2 + (10 ÷ 2) = 2 + 5
⇒ h = 7 inches.
We know the formula for area of parallelogram is given as follows :-
Area of parallelogram = base x height
Area of parallelogram = 10 inches x 7 inches
Area of parallelogram = 70 squared inches.
Hence, the final answer is 70 squared inches.
Answer:
he would need 21 tiles on each side. I think
Step-by-step explanation:
C is the answer because the fractions are not proportional.
Answer: C. 9/14, 3/4
