Answer:
Yes, \sqrt{2}(\sqrt{3.5} + 2\sqrt{5} )
Step-by-step explanation:
By roots property, the roots can be re-write as multiplications or division, like this:
![\sqrt[n]{a} . \sqrt[n]{b} =\sqrt[n]{ab}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20.%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%5Csqrt%5Bn%5D%7Bab%7D)
Here, we can re-write both roots:
and 
Now we have:
And we can take out the common expression:
⇒ Answer
Answer:
I looked at the picture and it looks nice
Step-by-step explanation:
I dont know the answer?
Answer:
where is only u trangle
Step-by-step explanation:
lol
Answer:
1
Step-by-step explanation:
(−4)−(−2)–{(−5)–[(−7)+(−3)–(−8)]}
-4 + 2 - {-5 - [-7 - 3 + 8]}
-2 - [-5 + 7 + 3 - 8]
-2 - (-3)
-2 + 3
1
Answer:
We know that:
If T = area of the triangle
and R = area of the rectangle:
I T - RI < 4.
Now, we know that:
T = 8*6/2 = 8*3 = 24
R = 4*(x - 4) = 4*x - 16
Then replacing those values, we can write:
I24 - (4*x - 16)I < 4
I40 - 4*xI < 4
Now let's solve it:
First we aim for the first value that is not a solutions, this is when:
I40 - 4*xI = 4
we can write this as:
40 - 4*x = +-4
The first extreme is:
40 - 4*x = +4
x = (40 - 4)/4 = 9
The other extreme is:
40 - 4*x = -4
x = (40 + 4)/4 = 11.
Then the set of solutions is: S = (9, 11)
