The answer to this is At least 16.6 meters in front of the reflecting surface.
The speed of sound without any interference is only about 340 m/s through the vibration of the media in which it passes through.
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Answer:
I think its 9.0397 Ohms
Explanation:
take the reciprocal of all the resistances: 1/15, 1/65, 1/35
then add them: = 151/1365
then reciprocal the answer: =1365/151
And chuck it on a calculator: =9.04 Ohms
I think this is right but I'm not entirely sure. Tell me if I'm right by the way!
Acceleration is the rate of change of velocity. Usually, acceleration means the speed is transforming, but not always. When an object moves in a circular path at a steady speed, it is still accelerating, because the focus of its velocity is changing.
a = 4,552 m / s², b) a = 2,588 m / s²
Newton's second law is
F = ma
a = F / m
in this case the force remains constant
indicate us
* for a mass m₁
a₁ = F/m₁
a₁ = 12, m/ s²
* for a mass m₂
a₂= 3.3 m / s²
acceleration m = m₂-m₁
substitute
let's calculate
1/a=1/3.3 - 1/12 = 0.21969
a = 4,552 m / s²
a= 4,552m/s²
<h3>What is speed and acceleration?</h3>
Speed estimates the rate of movement of an object, that is, the distance traveled per unit of time. Acceleration calculates the rate of change of velocity, that is, the change in velocity between two different moments
To learn more about Acceleration, refer
brainly.com/question/460763
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Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.