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Juli2301 [7.4K]
3 years ago
6

An athlete with mass m running at speed v grabs a light rope that hangs from a ceiling of height H and swings to a maximum heigh

t of h1. In another room with a lower ceiling of height H/2, a second athlete with mass 2m running at the same speed v grabs a light rope hanging from the ceiling and swings to a maximum height of h2. How does the maximum height reached by the 2 athletes compare and why? (Pick one) a) The first athlete reaches a greater height, because the athlete swings on a longer rope; b) The second athlete reaches a greater height, because the athlete has a greater mass; c) The 2 athletes reach the same height, because the effect of the rope length offsets the effect of the athletes’ masses; d) The 2 athletes reach the same height, because the athletes run with the same speed.
Physics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

d) The 2 athletes reach the same height, because the athletes run with the same speed.

Explanation:

In the whole process , kinetic energy is converted into potential energy .

1/2 m v² = mgh

v² = 2gh

h = v² / 2g

In this expression we see that height attained does not depend upon mass of the object . At the same time it also makes it clear that it depends upon velocity . As the velocity in both the cases are same , height attained by both of them will be same. Hence option d ) is correct.

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Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal
kirza4 [7]

At t =0, the velocity of A is greater than the velocity of B.

We are told in the question that the spacecrafts fly parallel to each other and that for the both  spacecrafts, the velocities are described as follows;

A: vA (t) = ť^2 – 5t + 20

B: vB (t) = t^2+ 3t + 10

Given that t = 0 in both cases;

vA (0) = 0^2 – 5(0) + 20

vA = 20 m/s

For vB

vB (0) = 0^2+ 3(0) + 10

vB = 10 m/s

We can see that at t =0, the velocity of A is greater than the velocity of B.

Learn more: brainly.com/question/24857760

Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?

3 0
3 years ago
A stationary siren emits sound of frequency 1000 Hz and wavelength 0.343 m. An observer who is moving toward the siren will meas
Ainat [17]

Answer:

f>1000Hz and wavelength=0.343 m

Explanation:

We are given that

Frequency of stationary siren,f=1000 Hz

Wavelength of stationary sound,\lambda=0.343 m

When a observer is moving towards the siren then the frequency increases.

Therefore,an observer who is moving towards the siren measure a frequency >1000 Hz.

The wavelength depends upon the speed of source.

But we are given that siren is stationary.

Therefore, source is not moving and then the wavelength remains same.

f>1000Hz and wavelength=0.343 m

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Clois what is the weight of a body in the earth, if its weig is 5Nin moon? <br>​
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A wheel is used to turn a valve stem on a water valve. How much is the mechanical advantage when an effort of 80 lbs. is applied
Ann [662]

Answer:

4

Explanation:

From the question given above, the following data were obtained:

Effort (E) = 80 lbs

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Mechanical advantage is simply defined as the ratio of load to effort. Mathematically, it is expressed as:

Mechanical advantage = Load / Effort

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With the above formula, we can obtain the mechanical advantage as illustrated below:

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MA = L / E

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Thus, the mechanical advantage is 4

3 0
3 years ago
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