600Hz is the driving frequency needed to create a standing wave with five equal segments.
To find the answer, we have to know about the fundamental frequency.
<h3>How to find the driving frequency?</h3>
- The following expression can be used to relate the fundamental frequency to the driving frequency;
f(n) = n * f (1)
where, f(1) denotes the fundamental frequency and the driving frequency f(n).
- The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.
f(4) = 4× f (1)
480 = 4× f(1)
f(1) = 480/4 =120Hz.
So, 120Hz is the fundamental frequency.
- To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
- For, n = 5,
f(n) = n 120Hz,
f(5) = 5×120Hz=600Hz.
Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.
Learn more about the fundamental frequency here:
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The correct answer is A) Ipsilateral
Explanation:
The term ipsilateral is commonly used to describe objects or structures that are on the same side of a body or structure. This term is correct to describe the right eye and the right lung because these two organs are on the same side of the body (the right side). This can also be used to describe other organs such as the left humerus and the left hand or the right ear and the right feet because these pairs are also on the same side. According to this, the correct answer is A.
Answer:
The difference in the decibel corresponses to a constant difference in the loudness perceived.
The refore the sound intensity from the orchestra is like 100 times that of the violin.
Explanation:
Answer: 1.91*10^8 N/m²
Explanation:
Given
Radius of the steel, R = 10 mm = 0.01 m
Length of the steel, L = 80 cm = 0.8 m
Force applied on the steel, F = 60 kN
Stress on the rod, = ?
Area of the rod, A = πr²
A = 3.142 * 0.01²
A = 0.0003142
Stress = Force applied on the steel/Area of the steel
Stress = F/A
Stress = 60*10^3 / 0.0003142
Stress = 1.91*10^8 N/m²
From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²
