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storchak [24]
3 years ago
9

A 2.0 kilogram mass is located 3.0 meters above the surface of earth. what is the magnitude of earth's gravitational field stren

ght at this location?
Physics
1 answer:
MissTica3 years ago
7 0
Why do you think its important for givernment offcials to take an oath of ofice?
You might be interested in
If the 250 kg bumper car that you are riding in hits another bumper car that is sitting still while driving 3.5 m/s, how much fo
Vilka [71]

Answer:

875 N

Explanation:

From this question, you didn't state the time taken for the bumper car to move or to hit the other bumper car. In calculations of force, time is often needed, because

Force = mass * acceleration, while

Acceleration = velocity / time, basically

Force = mass * velocity / time.

We have our mass, we have our velocity, but we haven't time. So, for this calculation, I'd assume our time to be 1s.

Going by the formula I stated, we can then say that

Force = 250 * 3.5 / 1

Force = 875 N

This means the force my bumper car have while moving at 3.5 m/s for an estimated time of 1s is 875 N

3 0
3 years ago
In which case would electrical potential energy be built up and stored in the electric field? a) A positive charge is moved towa
mr_godi [17]

Answer:

The correct option is B

Explanation:

Although, it is common knowledge that in an electric field, unlike charges attract and like charges repel. However, to build up an electric potential, a positive charge is brought close to another positive charge - this causes work done to be changed to electric potential energy and stored in the electric field.

It should however be noted that when a negative charge is moved away from a positive charge, the negative charge gains electric potential energy.

5 0
2 years ago
How many times did thomas edison fail before inventing the lightbulb
Rom4ik [11]

Answer:

he failed thousands of times

Explanation:

There is no known number for his failings. Edison may have failed in many of his experiments and in his schooling, but he had something better working in his favor. He had great determination and persistence.

He failed thousands of times in an attempt to develop an electric light, the great Edison simply viewed each unsuccessful experiment as the elimination of a solution that wouldn’t work, thereby moving him that much closer to a successful solution.

4 0
3 years ago
How are you going to describe the amount of force acting in the given situation?​
NeTakaya

Answer:

fully describe the force acting upon an object, you must describe both the magnitude (size or numerical value) and the direction. ... In contrast, 10 Newton, downward is a complete description of the force acting upon an object; both the magnitude (10 Newton) and the direction (downward) are given.

5 0
2 years ago
Read 2 more answers
A helicopter lifts a 81 kg astronaut 19 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
nexus9112 [7]

Answer:

a) The work done on the astronaut by the force from the helicopter is W_{h}=16087.68\ J.

b) The work done on the astronaut by the gravitational force is  W_{g}=-15082.2\ J .

Explanation:

We are told that the mass of the astronaut is m=81\ kg, the displacement is \Delta x=19\ m, the acceleration of the astronaut is  |\vec{a}|=\frac{g}{15}  and the acceleration of gravity is g=9.8\ \frac{m}{s^{2}} .

We suppose that in the vertical direction the force from the helicopter F_{h} is upwards and the gravitational force F_{g} is downwards. From the sum of forces we can get the value of F_{h}:

                                               F_{h}-F_{g}=m.a

                                              F_{h}-mg=m.\frac{g}{15}

                                              F_{h}=mg(1+\frac{1}{15})

                              F_{h}=(\frac{16}{15}).81\ kg.\ 9.8\ \frac{m}{s^{2}}\ \Longrightarrow\ F_{h}=846.72\ N

We define work as the product of the force, the displacement of the body and the cosine of the angle \theta between the direction of the force and the displacement of the body:

                                                 W=F.\Delta x.\ cos(\theta)

a) The work done on the astronaut by the force from the helicopter

                                                  W_{h}=F_{h}.\Delta x

                                             W_{h}=846.72\ N.\ 19\ m

                                                  W_{h}=16087.68\ J

b) The work done on the astronaut by the gravitational force

                                                   W_{g}=-F_{g}.\Delta x

                                                    W_{g}=-mg\Delta x

                                            W_{g}=-81\ kg.\ 9.8\ \frac{m}{s^{2}}.\ 19\ m

                                                  W_{g}=-15082.2\ J

                                             

                                                 

                                               

                                       

5 0
3 years ago
Read 2 more answers
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