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lina2011 [118]
3 years ago
12

If the distance between two objects is increased, the gravitational force will _____.

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

Decrease by the distance squared

Explanation:

Decrease by the distance squared

Mila [183]3 years ago
7 0

Answer:

Decrease by the distance squared

Explanation:

<u><em>Gravitation formula:</em></u>

F=\frac{GMm}{r^{2}}

where

'F' is the force of attraction between the two bodies (Gravitational force),

'G' is the universal gravitational constant,

'M' is the mass of the first object,

'm' is the mass of the second object and

'r'  is the distance between the centers of each object.

Hence, with the increase by distance between two objects , the gravitation decreases by the distance squared

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If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?
Semenov [28]

Answer:

see explanation below

Explanation:

The question is incomplete. Here's the complete question:

<em>Consider the following reaction: </em>

<em>SO2Cl2 -----> SO2(g) + Cl2(g) </em>

<em>Kc= 2.99 x 10^-7 at 227 degrees celcius </em>

<em>If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?</em>

This is a problem of equilibrium, therefore, we need to solve this using the expression of equilibrium constant. To do that, we need to wirte an ICE chart and solve from there:

       SOCl2 ---------> SO2 + Cl2     Kc = 2.99x10⁻⁷

i)       0.168                  0        0

c)         -x                    +x       +x

e)     0.168-x                x         x

Writting the Kc expression:

Kc = [SO2] [Cl2] / [SOCl2]

Replacing the values from the chart:

2.99x10⁻⁷ = x² / 0.168 - x

However, Kc is a very very small value, therefore, we can assume that the value of "x" would be very small too, and we can neglect the 0.168-x and just round it to 0.168:

2.99x10⁻⁷ = x²/0.168

2.99x10⁻⁷ * 0.168 = x²

√5.02x10⁻⁸ = x

x = 2.24x10⁻⁴ M

This means then, that the concentration of Cl2 in equilibrium would be:

<em>[Cl₂] = 2.24x10⁻⁴ M</em>

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