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2 years ago

If the distance between two objects is increased, the gravitational force will _____.

Chemistry

2 answers:

soldier1979 [14.2K]2 years ago

8 0

Answer:

Decrease by the distance squared

Explanation:

Decrease by the distance squared

Mila [183]2 years ago

7 0

Answer:

Decrease by the distance squared

Explanation:

Gravitation formula:

$F=\frac{GMm}{r^{2}}$

where

'F' is the force of attraction between the two bodies (Gravitational force),

'G' is the universal gravitational constant,

'M' is the mass of the first object,

'm' is the mass of the second object and

'r' is the distance between the centers of each object.

Hence, with the increase by distance between two objects , the gravitation decreases by the distance squared

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3 years ago

The enthalpy change for converting 1.00 mol of ice at -50.0 ∘c to water at 60.0∘c is ________ kj. the specific heats of ice, wat

guajiro [1.7K]

First, we have to get:

1- The heat required to increase T of ice from -50 to 0 °C:

according to q formula:

q1 = m*C*ΔT

when m is the mass of ice = mol * molar mass

= 1 mol * 18 mol/g

= 18 g

and C is the specific heat capacity of ice = 2.09 J/g-K

and ΔT change in temperature = 0- (-50) = 50°C

by substitution:

∴q1 = 18 g * 2.09 J/g-K *50°C

= 1881 J = 1.881 KJ

2- the heat required to melt this mass of ice is :

q2 = n*ΔHfus

when n is the number of moles of ice = 1 mol

and ΔHfus = 6.01 KJ/mol

by substitution:

q2 = 1 mol * 6.01 KJ/mol

= 6.01 KJ

3- the heat required to increase the water temperature from 0°C to 60 °C is:

q3 = m*C*ΔT

when m is the mass of water = 18 g

C is the specific heat capacity of water = 4.18 J/g-K

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by substitution:

∴q3 = 18 g * 4.18 J/g-K * 60°C

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