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lina2011 [118]
3 years ago
12

If the distance between two objects is increased, the gravitational force will _____.

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

Decrease by the distance squared

Explanation:

Decrease by the distance squared

Mila [183]3 years ago
7 0

Answer:

Decrease by the distance squared

Explanation:

<u><em>Gravitation formula:</em></u>

F=\frac{GMm}{r^{2}}

where

'F' is the force of attraction between the two bodies (Gravitational force),

'G' is the universal gravitational constant,

'M' is the mass of the first object,

'm' is the mass of the second object and

'r'  is the distance between the centers of each object.

Hence, with the increase by distance between two objects , the gravitation decreases by the distance squared

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How many moles of N2 are needed to make 5.0 moles of NH3?
Juli2301 [7.4K]

Answer:

The answer is "2.5 mole"

Explanation:

The reaction for producing NH_3 can be defined as follows:

Reaction:

N_2+ 3H_2 \rightarrow 2NH_3

According to the above reaction, to produce 2 moles of NH_3  we need 1 mole of nitrogen:

So, according to the question to produce 5.0 mole NH_3 the required N_2:

\Rightarrow \ 5.0 \ mole \ of \ NH_3  \times  \frac{1 \ mole\ of \ N_2}{2 \ mole \ of NH_3}\\\\\Rightarrow 5.0 \times \frac{1}{2}\\\\\Rightarrow 2.5\  mole\\

To produce 5.0 mole NH_3  we need 2.5 mole N_2

5 0
3 years ago
Suppose you start with a solution of red dye #40 that is 2.3 ✕ 10−5 M. If you do three successive volumetric dilutions pipetting
larisa [96]

Answer: Therefore, the concentration of final solution is 4.0\times 10^{-8}M

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 2.3\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

2.3\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.28\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.28\times 10^{-5}M

2) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.28\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.28\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.034\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.034\times 10^{-5}M

3) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.034\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.034\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=4.0\times 10^{-8}M

Therefore, the concentration of final solution is 4.0\times 10^{-8}M

5 0
3 years ago
What is the density of aluminum in grams per cubic centimeter?
oksano4ka [1.4K]

Answer:

Density of aluminum is 2.699 g/cm^3

Explanation:

Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:

Density = \frac{Mass}{Volume}

Units: g/cm^3 or kg/m^3

Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3

5 0
3 years ago
What are some examples of mixtures?
Flura [38]

Here are 5 examples of suspensions mixtures:

<span>1-mercury shaken in oil</span>

<span>2-oil shaken in water</span>

<span>3-powdered chalk in water </span>

<span>4-dust in air</span>

<span><span>5-soot in air</span></span>

<span><span>hope this helps
</span></span>

8 0
3 years ago
20. Explain, in terms of valence electrons, why the bonding in NaCl is ionic.
Ivahew [28]

Answer:

MgO, is similar to the bonding in barium chloride, BaCl2. The bonding in each compound involves a transfer of valence electrons from the metal to the nonmetal; both metals lose all of their valence electrons

Explanation:

used goggle

4 0
3 years ago
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