The question is incomplete, here is the complete question:
The given chemical reaction is:
![2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3](https://tex.z-dn.net/?f=2Al%2B3Cu%28NO_3%29_2%5Crightarrow%203Cu%2B2Al%28NO_3%29_3)
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
<u>Answer:</u> The theoretical yield of copper is 44.48 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of aluminium = 12.6 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:
![\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20aluminium%7D%3D%5Cfrac%7B12.6g%7D%7B27g%2Fmol%7D%3D0.467mol)
The given chemical equation follows:
![2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3](https://tex.z-dn.net/?f=2Al%2B3Cu%28NO_3%29_2%5Crightarrow%203Cu%2B2Al%28NO_3%29_3)
By Stoichiometry of the reaction:
2 moles of aluminium produces 3 moles of copper
So, 0.467 moles of aluminium will produce =
of copper
Now, calculating the mass of copper from equation 1, we get:
Molar mass of copper = 63.5 g/mol
Moles of copper = 0.7005 moles
Putting values in equation 1, we get:
![0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g](https://tex.z-dn.net/?f=0.7005mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20copper%7D%7D%7B63.5g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20copper%7D%3D%280.7005mol%5Ctimes%2063.5g%2Fmol%29%3D44.48g)
Hence, the theoretical yield of copper is 44.48 grams