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Novay_Z [31]
3 years ago
10

Can some one help with this question? "What is the relationships between. The force due to friction and the force due to gravity

? Is it true for all four surfaces? (wood, rubber, carpet, and sandpaper)
Physics
1 answer:
strojnjashka [21]3 years ago
5 0
Okay, so let's start off with the difference between the force of friction, and the force of gravity.
Friction, is when two things rub against each-other. (Such as tectonic plates.)
Gravity, is something being held down towards the center of the earth.
(They are both caused by forces.)

Let's imagine wood is being rubbed against your hand. It isn't very comfortable, yet it moves evenly over your skin.
Now, let's use rubber. The skin on your hand is moving back and forth, along with the rubber.
Carpet. This is moving over your skin, yet causing some irritation.
With sandpaper. It is moving over your hand slightly like the rubber was, except this is trying to shape your hand, so therefore it is causing irritation.

I hope this helped in some way. May not have been the exact thing you wanted, but this should help give you an idea. (:
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Jim rode at an average speed of 12mph in 2 hours the he walked at an average of speed of 3 mph 0.5 hours what was the total dist
mrs_skeptik [129]

Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

6 0
4 years ago
One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren
katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

\sigma = \frac{F}{A}

Where,

\sigma =Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

\sigma_y = \frac{F_y}{A}

where,

\sigma_y =Shear strength

F_y = Shear Force

A_0 =Parallel Area

PART A) Replacing with our values in the equation of tensile strenght, then

311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}

Resolving for F,

F= 1399.5N

PART B) We need here to apply the shear strength equation, then

\sigma_y = \frac{F_y}{A}

210*10^6 = \frac{F_y}{15*10^{-6}30*10^{-2}}

F_y = 945N

In such a way that the material is more resistant to tensile strength than shear force.

6 0
4 years ago
A ball is thrown vertically upward with a
Veronika [31]

Answer:

1) The maximum height reached is approximately 39.715 m

2) The time it takes the ball to reach the its highest point is approximately 2.85 s

Explanation:

1) The vertical velocity of the ball, u = 27.9 m/s

The acceleration due gravity, g = 9.8 m/s²

The kinematic equation that gives the height, h, reached by the ball is given as follows;

v² = u² - 2·g·h

Where;

v = The final velocity of the ball = 0 m/s at the maximum height

h = The height reached by the ball = h_{max} at maximum height

Therefore, by substitution of the known values, we have;

v² = u² - 2·g·h

0² = 27.9² - 2 × 9.8 × h_{max}

2 × 9.8 × h_{max} = 27.9²

h_{max} = 27.9²/(2×9.8) ≈ 39.715

The maximum height reached = h_{max} ≈ 39.715 m

2) From the kinematic equation of motion, v = u - g·t, we have the time, t, it takes the ball to reach the maximum height given as follows

At maximum height, the final velocity, v = 0 m/s, therefore, we have;

0 = 27.9 - 9.8 × t

9.8 × t = 27.9

t = 27.9/9.8 ≈ 2.85

The time it takes the ball to reach the maximum height = t ≈ 2.85 seconds.

6 0
3 years ago
A meat baster consists of a squeeze bulb attached to a plastic tube. When the bulb is squeezed and released, with the open end o
Misha Larkins [42]

Answer:P_{bulb}=99.11\ kPa

Explanation:

Given

When the bulb is squeezed then liquid level rises to height h i.e. pressure decreases inside the bulb which causes rises in the tube

for common elevation i.e. at liquid level pressure must be equal therefore

P_{bulb}+\rho gh=P_{atm}

P_{bulb}=1.013\times 10^5-1490\times 9.8\times h

for h=0.15\ m

P_{bulb}=1.013\times 10^5-1490\times 9.8\times 0.15

P_{bulb}=101.3\times 10^3-2.1903\times 10^3

P_{bulb}=99.11\ kPa

for h=0.1\ m

P_{bulb}=101.3\times 10^3-1.4602\times 10^3  

P_{bulb}=99.83\ kPa

8 0
3 years ago
Please help, have no idea on how to solve it. Joel is pulling a sled up a hill at an angle of 30 degrees above the horizontal fo
lubasha [3.4K]

Answer:

-1m

Explanation:

I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)

If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.

Resultant vectors are the sum of vectors.

The sum of vectors is equal to 5m + - 6m = -1m

6 0
3 years ago
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