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Novay_Z [31]
2 years ago
10

Can some one help with this question? "What is the relationships between. The force due to friction and the force due to gravity

? Is it true for all four surfaces? (wood, rubber, carpet, and sandpaper)
Physics
1 answer:
strojnjashka [21]2 years ago
5 0
Okay, so let's start off with the difference between the force of friction, and the force of gravity.
Friction, is when two things rub against each-other. (Such as tectonic plates.)
Gravity, is something being held down towards the center of the earth.
(They are both caused by forces.)

Let's imagine wood is being rubbed against your hand. It isn't very comfortable, yet it moves evenly over your skin.
Now, let's use rubber. The skin on your hand is moving back and forth, along with the rubber.
Carpet. This is moving over your skin, yet causing some irritation.
With sandpaper. It is moving over your hand slightly like the rubber was, except this is trying to shape your hand, so therefore it is causing irritation.

I hope this helped in some way. May not have been the exact thing you wanted, but this should help give you an idea. (:
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A fox runs for 12 seconds at a speed of 9.65 m/s. How much distance does it cover? Exact answer, do NOT round.
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115.8

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Your GPS shows that your friend’s house is 10.0 km away. But there is a big hill between your houses and you don’t want to bike
kati45 [8]

Answer:

The value is c  = 8 \  km

Explanation:

From the question we are told that

The distance of friends house from your point is a =  10 \  km

The distance of your friends street from your street is b =  6 \  km \  in the \ direction \  towards \  the  \  north

The diagram illustrating this question is shown on the first uploaded image

From the diagram we can apply by Pythagoras theorem as follows

a^2 =  b^2 +  c^2

=>     c  =  \sqrt{^2 -  b^2}

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3 years ago
All of the following are functions of the sensory somatic nervous system except
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6 0
3 years ago
Read 2 more answers
A rectangular tank is filled to a depth of 10m with freshwater and open to air at atmospheric pressure.
charle [14.2K]

Answer:

<em>1.</em> <em>39068.07 N</em>

<em>2. 19534.036 N</em>

Explanation:

depth of water h = 10 m

atmospheric pressure Patm = 101325 Pa

density of water p = 1000 kg/m^3

acceleration due to gravity g = 9.81 m/s^2

pressure due to depth of water = pgh

P = 1000 x 9.81 x 10 = 98100 Pa

total pressure on the bottom of the tank is Patm + p = 101325 + 98100 = 199425 Pa

Left plug has diameter = 50 cm = 0.5 m

radius = 0.5/2 = 0.25 m

height = 1 cm = 0.01 m

<em>height below tank surface = 10 - 0.01 = 9.99</em>

pressure at this depth =  1000 x 9.81 x 9.99 = 98001.9 Pa

<em>total pressure = Patm + P = 101325 + 98001.9 = 199326.9 Pa</em>

surface area of plug = πr^{2} = 3.142 x 0.25^{2} = 0.196 m^{2}

<em>force required to lift left plug = pressure x area</em>

F =  199326.9 x 0.196 = <em>39068.07 N</em>

<em>The right side is a hemisphere with the same diameter, therefore surface area is half of the left plug</em>

A = 0.196/2 = 0.098 m^{2}

force F required to lift right plug =  199326.9  x 0.098 =<em> 19534.036 N</em>

6 0
3 years ago
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