The answer is false hope this helps
A calculator must be used. To put your calculator in degree mode, press the MODE button and select degree, the press the 2nd button then MODE again. For most TI calculators, press the 2nd button then press the cos button then enter the value 0.34. This will give you an answer of 70.123 (when you round to 3 decimal places).
The answer is C
We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²
Answer:
Force exerted by the lighter block on the heavier block is 6.63 N
Explanation:
Given Data
F = 80N
m = 1kg
M = 11kg
Solution:
*We assume that there is no friction
Calculating the acceleration of the system
a = 
a = 
a = 
a = 6.67m
Let's write the Equation of Motion of the heavier block
= F - 
Ma = F - 
force exerted by the lighter block on the heavier block is calculated as
= F - Ma
= 80 - (11 x 6.67)
= 6.63 N