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DerKrebs [107]
3 years ago
15

Which ingredient would a company that makes super sour candy most likely use in a large quantity

Physics
2 answers:
stiks02 [169]3 years ago
4 0
Suger........................

lina2011 [118]3 years ago
4 0

Answer:

The answer is citric acid.

Explanation:

Citric acid is found commonly in cirtrus fruits, giving that sour tangy taste, so by adding that to candy, it makes it sour.

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A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s
kkurt [141]

Answer:

\Large \boxed{\mathrm{5.67 \ seconds }}

Explanation:

\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}

\displaystyle A \ = \ \frac{V_f - V_i }{t}

\displaystyle 3 \ = \ \frac{25 - 8 }{t}

\displaystyle 3 \ = \ \frac{17 }{t}

\displaystyle t \ = \ \frac{17 }{3} \approx 5.67

4 0
3 years ago
Newton's "quantity of motion" is conservation.<br><br> True<br><br> False
Valentin [98]
The answer is false hope this helps
6 0
3 years ago
Read 2 more answers
What is cos-^1(0.34)?<br> A. 19.9<br> B. 44.2°<br> C. 70.1°<br> D. 18.8°
Fudgin [204]
A calculator must be used. To put your calculator in degree mode, press the MODE button and select degree, the press the 2nd button then MODE again. For most TI calculators, press the 2nd button then press the cos button then enter the value 0.34. This will give you an answer of 70.123 (when you round to 3 decimal places).

The answer is C
3 0
3 years ago
A train starts from rest and accelerates uniformly, until it has traveled 3.7 km and acquired a velocity of 26 m/s. What is the
bogdanovich [222]
We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²

7 0
3 years ago
Consider the following system, where F = 80 N, m = 1 kg, and M = 11 kg M m F What is the magnitude of the force with which one b
Lorico [155]

Answer:

Force exerted by the lighter block on the heavier block is 6.63 N

Explanation:

Given Data

F = 80N

m = 1kg

M = 11kg

Solution:

*We assume that there is no friction

Calculating the acceleration of the system

a = \frac{F}{m+M}

a = \frac{80}{1+11}

a = \frac{80}{12}

a = 6.67ms^{-2}

Let's write the Equation of Motion of the heavier block  

F_{1} = F - F_{2}

Ma = F - F_{2}

force exerted by the lighter block on the heavier block is calculated as

 F_{2} = F - Ma

 F_{2} = 80 - (11 x 6.67)  

 F_{2} = 6.63 N

8 0
3 years ago
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