**The minimum work needed is 1456.4 J for 1 meter of ramp**

**Explanation:**

There is one force pushing the car down along the slope: the component of the weight parallel to the slope, which is given by

where

m = 950 kg is the mass of the car

is the acceleration of gravity

is the angle of the ramp

Therefore, the minimum force needed to push the car up along the ramp must be equal to this force:

The minimum work done to push the car along the ramp is therefore:

where d is the length of the ramp. In this problem, it is not specified, so I assume it is

d = 1 m

And therefore, the minimum work required is:

Learn more about **work:**

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**Answer:**

60m/s

**Explanation:**

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

**Answer:**

I think the answer is option 3

**Answer:**

400 Watts

**Explanation:**

The main function of a voltage transformer is to change alternating current (ac) voltage from one voltage level to another. The relationship between the primary coil and secondary coil of a transformer is a function of ratio of the voltage or current and number of turns or loop. The ratio of the voltages between the two coils is equal to the ratio of number of loops in the two coils.

Varying the number of winding in the primary and secondary coils allows the transformer to step-up or step-down voltages while power is neither increased nor decreased in the primary or secondary except for some minor losses such as iron losses, copper losses, hysteresis losses, eddy current losses, stray loss, and dielectric losses. Therefore, the power in the primary and secondary are the same. The power supplied to the 20-ohm resistor terminal in the secondary coil will be 400 Watts.