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3 years ago

4. If you were an astronaut on the Moon, what would you experience? What would you see from your perspective?

Physics

2 answers:

hjlf3 years ago

8 0

an astronaut on the Moon could experience zero gravity, and would see stars and Earth.

klio [65]3 years ago

8 0

Answer:

Since Moon's gravity is 0.167 times the gravity of Earth, astronaut would weigh very less. He would not be able to walk and would be to able to jump to large distance. Also, due to lack of atmosphere, the sky would appear black and stars would be visible all the time. The Earth would also have phases as viewed from the Moon.

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What do executive departments do?

enot [183]

Answer:

Image result for What do executive departments do?

Under Article II of the Constitution, the President is responsible for the execution and enforcement of laws created by Congress. Fifteen executive departments—each led by an appointed member of the President's Cabinet—carry out the day-to-day administration of the Federal Government.

Explanation:

The Cabinet and independent federal agencies are responsible for the day-to-day enforcement and administration of federal laws. ... Fifteen executive departments — each led by an appointed member of the President's Cabinet — carry out the day-to-day administration of the federal government.

8 0

3 years ago

What is another way of saying “getting the smallest possible force”?

Dmitriy789 [7]

Answer:

MOMENTUM

Explanation:

another way of saying getting the smallest force possible is the word " MOMENTUM".

momentum is the ability to keep maintaining,incresing or itself developing to move at constant speed or to increase the speed.

7 0

3 years ago

A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the

Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

$-F_{f} + F = 0$

$-F_{f} + ma = 0$

$\mu mg = ma$

$\mu = \frac{a}{g}$

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

$v_{f}^{2} = v_{0}^{2} + 2ad$

$a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}$

Where:

d: is the distance traveled = 46.1 m

$v_{f}$ : is the final speed of the truck = 0 (it stops)

$v_{0}$ : is the initial speed of the truck = 17.9 m/s

$a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}$

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.

$\mu = \frac{a}{g}$

$\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}$

$\mu = 0.35$

Therefore, the minimum coefficient of friction required is 0.35.

I hope it helps you!

4 0

3 years ago

Compute the torque about the origin of the gravitational force F--mgj acting on a particle of mass m located at 7-xî+ yj and sho

Andrews [41]

Answer:

Explanation:

Force, F = - mg j

r = - 7x i + y j

Torque is defined as the product f force and the perpendicular distance.

It is also defined as the cross product of force vector and the displacement vector.

$\overrightarrow{\tau }=\overrightarrow{r}\times \overrightarrow{F}$

$\overrightarrow{\tau }=(- 7 x i + yj)\times (-mgj)$

[tex]\overrightarrow{\tau }= 7 m g x k

Here, we observe that the torque is independent of y coordinate.

3 0

3 years ago

An 800 N man climbs 5 m up a ladder. How much gravitational potential energy does he gain?

Artemon [7]

Answer:

4000J

Explanation:

Given parameters:

Weight of the man = 800N

Height of ladder = 5m

Unknown:

Gravitational potential energy gained = ?

Solution:

The gravitational potential energy is due to the position of a body.

Gravitational potential energy = weight x height

Now insert the parameters;

Gravitational potential energy = 800 x 5 = 4000J

5 0

3 years ago