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telo118 [61]
3 years ago
10

List some benefits of Cardiovascular exercise:

Physics
2 answers:
saveliy_v [14]3 years ago
7 0

Answer:

reduced heart attack chance

Explanation:

cholestrol buildups get destroyed by high pressure blood

uwu

lozanna [386]3 years ago
3 0

Answer:

Aerobic exercise reduces the risk of many conditions, including obesity, heart disease, high blood pressure, type 2 diabetes, metabolic syndrome, stroke and certain types of cancer. Weight-bearing aerobic exercises, such as walking, help decrease the risk of osteoporosis.

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The heaviest piece of equipment ever carried by plane was 12,400.05kg generator built in Germany in 1993.How far above the groun
nadezda [96]

Answer:

754.6 m

Explanation:

The GPE (Gravitational potential energy) of an object with respect to the ground is given by

GPE = mgh

where

m is the mass of the object

g = 9.8 m/s^2 is the acceleration due to gravity

h is the heigth above the ground

Here we have

m = 12,400.05 kg is the mass

GPE = 91,700,000.00J is the GPE

Solving the formula for h, we find the heigth:

h=\frac{GPE}{mg}=\frac{91,700,000.00J}{(12,400.05 kg)(9.8 m/s^2)}=754.6 m

7 0
4 years ago
What is the difference between liquid and fluid friction
frez [133]
Friction is used to refer to forces that resist relative motion, in general,whereas viscosity refers specifically to resistive forces that occur between layers of a fluid when fluids attempt to flow. Fluid friction is the force that resists the movement of a solid object through a fluid(liquid or gas). Sky divers falling down through the sky experience a type of fluid frictioncalled air resistance.
6 0
4 years ago
We know that a ship, even though it is madeup of tonnes of iron, floats on water. How do you feel about the scientists who found
slamgirl [31]
I feel admiration and respect for them, and I feel grateful and humble.
3 0
3 years ago
A 55kg cart is pushed by a force of 225 n. what is the carts acceleration?
gayaneshka [121]
F=ma so a=F/m
a=225/55=4.09 m/sec^2
3 0
4 years ago
If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
Gnom [1K]

The average current density in the wire is given by:

J=\frac{I}{A}

where I is the current intensity and A is the cross-sectional area of the wire.


The cross-sectional area of the wire is given by:

A=\pi r^2

where r is the radius of the wire. In this problem, r=\frac{d}{2}=\frac{2.0 mm}{2}=1.0 mm=0.001 m, so the cross-sectional area is

A=\pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2


and the average current density is

J=\frac{I}{A}=\frac{2.4 A}{3.14 \cdot 10^{-6} m^2}=7.64 \cdot 10^5 A/m^2

8 0
3 years ago
Read 2 more answers
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