Answer:
w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
Explanation:
We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is
w² = mg d / I
In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow
d = L / 2
The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated
I = ¼ m r2 + ⅓ m L2
I = m (¼ r2 + ⅓ L2)
now let's use the concept of density to calculate the mass of the system
ρ = m / V
m = ρ V
the volume of a cylinder is
V = π r² L
m = ρ π r² L
let's substitute
w² = m g (L / 2) / m (¼ r² + ⅓ L²)
w² = g L / (½ r² + 2/3 L²)
L >> r
w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
One atom on nitrogen because there isn’t a number directly after it’s the 3 signifies that there is three groups of those atoms as a total
<span>Two sound waves of equal amplitude interfere so that the compression of one wave falls on the rarefaction of the other. The statement which is true is that A. no sound is heard.
These waves interfere, which means that their equal amplitudes match and thus cancel each other out, which is why there is no sound.
</span>
1. Take a breaker
2. Put a sieve on it
3. Pour the mixture and shake the sieve gently
4. Wait for the flour to fall. After the flour falls pour the rice from the sieve into other beaker then do experiment again for fair testing(optional)
Answer:
Explanation:
Using the given equation, we calculate the energy associated with the excited state 
and 
Helium has an atomic number (Z) equal to 2, for n=8:
For n=4:
When an electron jumps from an energy level with greater energy 
to one with lower energy 
the wavelength of the emitted photon is given by:
h is the Planck constant and c the speed of light in vaccum. So, we have:
