Answer:
0 J
Explanation:
= Work done on the satellite in circular orbit about earth by earth
= Force on gravity on satellite by earth
= displacement of the satellite
= Angle between the force on gravity and displacement = 90
We know that, Work done is given as
![W = F d Cos\theta\\W = F d Cos90\\W = F d (0)\\W = 0 J](https://tex.z-dn.net/?f=W%20%3D%20F%20d%20Cos%5Ctheta%5C%5CW%20%3D%20F%20d%20Cos90%5C%5CW%20%3D%20F%20d%20%280%29%5C%5CW%20%3D%200%20J)
The initial kinetic energy of the car is
![E_1 = \frac{1}{2}mv_1^2 = 1.9 \cdot 10^3 J](https://tex.z-dn.net/?f=E_1%20%3D%20%20%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2%20%3D%20%201.9%20%5Ccdot%2010%5E3%20J)
Then, the velocity of the car is decreased by half:
![v_2 = \frac{v_1}{2}](https://tex.z-dn.net/?f=v_2%20%3D%20%20%5Cfrac%7Bv_1%7D%7B2%7D%20%20)
so, the new kinetic energy is
![E_2 = \frac{1}{2}mv_2 ^2 = \frac{1}{2} m ( \frac{v_1}{2} )^2= \frac{1}{2}m \frac{v_1^2}{4}= \frac{E_1}{4}](https://tex.z-dn.net/?f=E_2%20%3D%20%20%5Cfrac%7B1%7D%7B2%7Dmv_2%20%5E2%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20m%20%28%20%5Cfrac%7Bv_1%7D%7B2%7D%20%29%5E2%3D%20%5Cfrac%7B1%7D%7B2%7Dm%20%5Cfrac%7Bv_1%5E2%7D%7B4%7D%3D%20%5Cfrac%7BE_1%7D%7B4%7D%20%20%20%20%20)
So, the new kinetic energy is 1/4 of the initial kinetic energy of the car. Numerically:
Answer:
See the explanation below
Explanation:
The watt (the power) is equal to the relationship between the work and the time in which that work is performed.
![P = W/t](https://tex.z-dn.net/?f=P%20%3D%20W%2Ft)
where:
W = work [J] (units of Joules)
t = time [s].
Now 1000 [W] are equal to 1 [kW]
And 1000000 [W] are equal to 1 [MW]
The horsepower is the unit of power in the imperial system of units.
And 745.7 [W] are equal to 1 [Hp]
Answer:
I just want the points but you should pay attention in class jk
It'll speed up in the direction it's being pushed unbalanced. Or, it could slow down if applied the right amount of unbalanced power. And finally if the unbalanced push is pushed it could change the direction of it's current motion it was traveling.<span>
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