Answer:
1. a) 0.5 h = 1,800 s
h) 20 cm = 0.2 m
b) 2.0 h = 7,200 s
i) 5.0 kg = 5,000 g
c) 3.5 h = 12,600 s
j) 1.5 kg = 1,500 g
d) 1/4 h = 900 s
k) 450.0 g = 0.45 kg
e) 3.0 m = 300 cm
l) 20.0 g = 0.02 kg
f) 2.5 m = 250 cm
m) 500.0 g = 0.5 kg
g) 0.5 m = 500 mm
n) 1000.0 g = 1 kg
Answer:
therefore critical angle c= 69.79°
Explanation:
Canola oil is less dense than water, so it floats over water.
Given
which is higher than that of water
refractive index of water
to calculate critical angle of light going from the oil into water
we know that
now putting values we get
c=
c=69.79°
therefore critical angle c= 69.79°
Answer:
Explanation:
For answer this we will use the law of the conservation of the angular momentum.
so:
where is the moment of inertia of the merry-go-round,
is the initial angular velocity of the merry-go-round,
is the moment of inertia of the merry-go-round and the child together and
is the final angular velocity.
First, we will find the moment of inertia of the merry-go-round using:
I =
I =
I = 359.375 kg*m^2
Where is the mass and R is the radio of the merry-go-round
Second, we will change the initial angular velocity to rad/s as:
W = 0.520*2 rad/s
W = 3.2672 rad/s
Third, we will find the moment of inertia of both after the collision:
Finally we replace all the data:
Solving for :