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leonid [27]
3 years ago
5

TRUE of FALSE: The human body responds to stressors by activating the nervous

Physics
1 answer:
melamori03 [73]3 years ago
8 0
That is false I think sorry if its not correct
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A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01 ???? 10
SIZIF [17.4K]

Answer:

the ratio of the bubble’s volume at the top to its volume at the bottom is 1.019

Explanation:

given information

h = 0.2 m

P_{0} = 1.01  x 10^{5} Pa

P_{1} V_{1} = P_{2} V_{2}

\frac{V_{2} }{V_{1}} = \frac{P_{1} }{P_{2}}

P_{1}  = P_{0}  + ρgh, ρ = 1000 kg/m^{3}

P_{1}  = 1.01 x 10^{5} Pa + (1000 x 9.8 x 0.2) = 1,0296 x 10^{5} Pa

P_{2}  = P_{0}  = 10^{5} Pa

thus,

\frac{V_{2} }{V_{1}} = 1,0296 x [tex]10^{5}/10^{5} = 1.019

8 0
3 years ago
What are the 3 tools used to collect weather data
sergey [27]
Anemometer, Psychrometer, <span>Barometer</span>
5 0
2 years ago
A virtual image formed by convex lens is always
natita [175]

Answer:

2. erect and magnified

4 0
3 years ago
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Monochromatic light of wavelength 687 nm is incident on a narrow slit. On a screen 1.65 m away, the distance between the second
Sophie [7]

Answer:

a ) 1.267 radian

b ) 1.084 10⁻³ mm

Explanation:

Distance of screen D = 1.65 m

Width of slit d = ?

Wave length of light   λ  = 687 nm.

Distance of second minimum fro centre y = 2.09 cm

Angle of diffraction = y / D

=  2.09 /1.65  

= 1.267. radian

Angle of diffraction of second minimum

= 2 λ / d

so 2 λ / d = 1.267

d = 2 λ / 1.267 = (2 x 687 ) /1.267 nm

=1084.45 nm = 1.084 x 10⁻³ mm.

3 0
2 years ago
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Y_f = V_yt  - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m

Therefore, the final position made with the vertical is 2.77 m.

3 0
2 years ago
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