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djverab [1.8K]
3 years ago
11

Which paper folding method can be used to form the midpoint of a line segment

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0

Hi !

Answer:

<em />

<em> Begin with a line segment on the paper and fold the paper so that the segment's endpoints lie on top of each other.</em>

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Please help, will mark brainliest<br><br>50 points
liraira [26]

Answer:

(-6,8)

Step-by-step explanation:

2x + 9y = 60

-9x + y = 62 --> y = 9x + 62 --> 2x + 9(9x + 62) = 60 -->

2x+ 81x + 558 = 60 -->

83x + 558 = 60 -->

83x = -498 -->

x = -6 -->

y = 9(-6) + 62 -->

y = 8

3 0
3 years ago
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Angie states the following:
kicyunya [14]
The answer is letter D, Angie is incorrect since triangles with two pairs of congruent sides and one pair of congruent angles do not necessarily meet the SAS orientation.
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3 years ago
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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Here are three stories:
aev [14]

Answer:

1)

a) 6x+3 = 27

b) x=4

c) We know that x is price of each ticket, so The price of each ticket is $4. They bought 6 tickets, so total cost of ticket = 24 and $3 for parking so, total money spent = $27.

2)

a) 3x + 6 = 27

b) x= 7

c) We know that x is amount of juice poured, so 3 friends of Diego will get 7 ounces of Juice, while Diego will get 6 ounces of juice.

3)

a) 27x + 3 = 6

b) x= 1/9

c) We know that x is time spend on each picture, so Jada spend 1/9 hour on each picture

Step-by-step explanation:

1. A family buys 6 tickets to a show. They also pay a $3 parking fee. They spend $27 to see the  show.

a)  Decide which equation represents each story. What does x represent in each equation?

Let x be price of one ticket.

The equation will be: 6x+3 = 27

b. Find the solution to each equation. Explain or show your reasoning,

Now solving the equation:

6x+3=27

6x=27-3

6x=24

x=24/6

x=4

So, we get x = 4

c. What does each solution tell you about its situation?

We know that x is price of each ticket, so The price of each ticket is $4. They bought 6 tickets, so total cost of ticket = 24 and $3 for parking so, total money spent = $27.

2. Diego has 27 ounces of juice. He pours equal amounts for each of his 3 friends and has 6  ounces left for himself.

a)  Decide which equation represents each story. What does x represent in each equation?

Let x be amount of juice poured.

The equation will be: 3x+6 = 27

b. Find the solution to each equation. Explain or show your reasoning,

Now solving the equation:

3x+6=27

3x=27-6

3x=21

x=21/3

x=7

So, we get x = 7

c. What does each solution tell you about its situation?

We know that x is amount of juice poured, so 3 friends of Diego will get 7 ounces of Juice, while Diego will get 6 ounces of juice.

3. Diego has 27 ounces of juice. He pours equal amounts for each of his 3 friends and has 6  ounces left for himself.

a)  Jada works for 6 hours preparing for the art fair. She spends 3 hours on a sculpture and  then paints 27 picture frames.

Let x be time spend on each picture frame.

The equation will be: 27x+3=6

b. Find the solution to each equation. Explain or show your reasoning,

Now solving the equation:

27x+3=6

27x=6-3

27x=3

x=3/27

x=1/9

So, we get x = 1/9

c. What does each solution tell you about its situation?

We know that x is time spend on each picture, so Jada spend 1/9 hour on each picture

8 0
3 years ago
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rding to linear pattern. If the initial value of the vehicle is $26,000, and the value ten years later is $0, what will the depr
Verdich [7]
The answer will be 5,200
3 0
4 years ago
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