Question

64 • 16^-3x = 16^3x-2

Answer 1

Answer:

$x = \dfrac{7}{12}$

Step-by-step explanation:

$64 \cdot 16^{-3x} = 16^{3x-2}$

$4^3 \cdot (4^2)^{-3x} = (4^2)^{3x-2}$

$4^3 \cdot 4^{-6x} = 4^{6x-4}$

$4^{-6x+3} = 4^{6x-4}$

$-6x+3 = 6x-4$

$-12x = -7$

$x = \dfrac{7}{12}$