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3 years ago

How does cellular respiration identify as a combustion reaction?

1 answer:

7 0

reactions to break down glucose using oxygen to produce carbon dioxide, water and energy in the form of ATP. ... To balance the oxygen atoms for the reactant side, you need to count 6 atoms from the glucose.

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The most common form if matter in the universe is____?

Rashid [163]

I am almost positive that the answer is: Plasmas. Let me know if im right or not please!! :)

7 0

3 years ago

A cylinder with a piston is full of gas which of the following actions would result in an increase in the pressure of the gas be

SpyIntel [72]

The answer is B. Decreasing the cylinder volume decreases the amount of space the gas has to occupy there for increasing pressure

7 0

3 years ago

Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00

Simora [160]

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

[OH^-]=10^(-pOH)

=10^-5

=1.00 x 10^-5 M

4 0

2 years ago

Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfu

erica [24]

Answer:

194.6 mL of SO₂

Explanation:

The reaction that takes place is:

P₄S₃ + 6O₂(g) → P₄O₁₀ + 3SO₂(g)

To solve this problem we need to use PV=nRT, so first let's convert the given units:

23.8 °C → 23.8 + 273.15 = 296.95 K

747 torr → 747/760 = 0.983 atm

We need to calculate V, so in order to do that we calculate n, using the mass of the reactant (P₄S₃):

0.576 g P₄S₃ * $\frac{1molP_{4}S_{3}}{220gP_{4}S_{3}} *\frac{3molSO_{2}}{1molP_{4}S_{3}}$ = 7.85 * 10⁻³ mol SO₂ = n

Now we calculate V:

PV=nRT

0.983 atm * V = 7.85 * 10⁻³ mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.95 K

V = 0.1946 L

Finally we convert L into mL:

0.1946 * 1000 = 194.6 mL

8 0

3 years ago

A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution

madam [21]

Answer: The initial pH of the HCl solution is 3

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL$

Putting values in above equation, we get:

$1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M$

1 mole of HCl produces 1 mole of $H^+$ ions and 1 mole of $Cl^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.001M$

Putting values in above equation, we get:

$pH=-\log (0.001)\\\\pH=3$

Hence, the initial pH of the HCl solution is 3

6 0

3 years ago