In an MO (molecular orbital) scheme for CH4, Group of answer choices ..there are three equivalent bonding MOs of equal energy an
1 answer:
Answer:
there are three equivalent bonding MOs of equal energy and one unique bonding MO.
Explanation:
Let us recall that according to the principles of the molecular orbital theory, when a compound is formed, the number of bonding molecular orbitals must be equal to the number of antibonding molecular orbitals.
Now methane is formed from one carbon atom and four hydrogen atoms. There are four bonding molecular orbitals and four antibonding molecular orbitals.
Three out of the four bonding molecular orbitals are degenerate while one is unique.
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Answer:
Most viscous to least viscous:
Explanation:
For hydrocarbons, viscosity increases with increasing molar mass. Because increasing molar mass signifies increase in number of electrons in molecules.
We know that in non-polar hydrocarbons, only van der waal intermolecular force exists. Van der waal force is proportional to number of electrons in a molecule.
Therefore with increasing molar mass, van der waal force increases. hence molecules gets more tightly bind with each other resulting increase in viscosity.
Here molar mass order :
Therefore viscosity order :