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kari74 [83]
3 years ago
12

In an MO (molecular orbital) scheme for CH4, Group of answer choices ..there are three equivalent bonding MOs of equal energy an

d one unique bonding MO. ..there are four equivalent bonding MOs of equal energy. ..there are two sets of doubly degenerate bonding MOs. ..there are four bonding MOs, each of different energy.
Chemistry
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

there are three equivalent bonding MOs of equal energy and one unique bonding MO.

Explanation:

Let us recall that according to the principles of the molecular orbital theory, when a compound is formed, the number of bonding molecular orbitals must be equal to the number of antibonding molecular orbitals.

Now methane is formed from one carbon atom and four hydrogen atoms. There are four bonding molecular orbitals and four antibonding molecular orbitals.

Three out of the four bonding molecular orbitals are degenerate while one is unique.

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marin [14]
<span>Myoglobin, like most proteins, has a complex three dimensional structure that is formed from many twisted helices. There are more than one helix, and it does not look like beads on a straight piece of string. It is not branched.</span>
4 0
3 years ago
If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
8 0
4 years ago
Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully rea
gulaghasi [49]

Answer:

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na(s)  + Cl₂(g)  →  2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol . 23 g/mol = 105.8 g

3 0
3 years ago
Help me I got stuck<br> Pls
Sophie [7]
The answer is C because the weight is going down so they form a gas.
3 0
3 years ago
How many grams of aluminum is produced when 82.4 grams of aluminum chloride
yKpoI14uk [10]

Answer:

16.6 g of Al are produced in the reaction of 82.4 g of AlCl₃

Explanation:

Let's see the decomposition reaction:

2AlCl₃ →  2Al  + 3Cl₂

2 moles of aluminum chloride decompose to 2 moles of solid Al and 3 moles of chlorine gas.

We determine the moles of salt:

82.4 g . 1mol/ 133.34g = 0.618 moles

Ratio is 2:2. 2 moles of salt, can produce 2 moles of Al

Then, 0.618 moles of salt must produce 0.618 moles of Al.

Let's convert the moles to mass → 0.618 mol . 26.98g /mol = 16.6 g

6 0
3 years ago
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