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kari74 [83]
3 years ago
12

In an MO (molecular orbital) scheme for CH4, Group of answer choices ..there are three equivalent bonding MOs of equal energy an

d one unique bonding MO. ..there are four equivalent bonding MOs of equal energy. ..there are two sets of doubly degenerate bonding MOs. ..there are four bonding MOs, each of different energy.
Chemistry
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

there are three equivalent bonding MOs of equal energy and one unique bonding MO.

Explanation:

Let us recall that according to the principles of the molecular orbital theory, when a compound is formed, the number of bonding molecular orbitals must be equal to the number of antibonding molecular orbitals.

Now methane is formed from one carbon atom and four hydrogen atoms. There are four bonding molecular orbitals and four antibonding molecular orbitals.

Three out of the four bonding molecular orbitals are degenerate while one is unique.

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8. Balance the following nuclear equations:<br> ^65/30Ca -&gt; ^65/29Sc +_______
a_sh-v [17]

Explanation:

          ⁶⁵₃₀Ca   →   ⁶⁵₂₉Sc  +   ⁿₓH

The reaction above is nuclear reaction.

In a nuclear reaction, the mass number and atomic number must be conserved.

The mass number is the superscript before the atom

Atomic number is the subscript before the atom

  Conserving mass number:

       65 = 65 + n

        n = 0

   conserving atomic number:

    30 = 29 + x

     x = 1

The unknown atom is a positron i.e a positively charged electron:   ⁰₁e

              ⁶⁵₃₀Ca   →   ⁶⁵₂₉Sc  +  ⁰₁e

learn more:

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3 0
3 years ago
By what method do we measure the distance to objects that are a few thousand light-years away?
Zigmanuir [339]

Answer:

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Explanation:

8 0
3 years ago
Read 2 more answers
BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w
Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is <u>5.44</u>

Explanation:

Given: The base dissociation constant: K_{b} = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: K_{w} = 1 × 10⁻¹⁴

<em><u>The acid dissociation constant </u></em>(K_{a})<em><u> for the weak acid (BH⁺) can be calculated by the equation:</u></em>

K_{a}. K_{b} = K_{w}    

\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}

\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}

<em><u>Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:</u></em>

Reaction involved: BH⁺  +  H₂O  ⇌  B  +  H₃O+

Initial:                     0.1 M                    x         x            

Change:                   -x                      +x       +x

Equilibrium:           0.1 - x                    x         x

<u>The acid dissociation constant: </u>K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}

\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}

\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}

As, x

\Rightarrow 0.1 - x = 0.1

\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }

\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}

\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}

<u>Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M</u>

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

<u>Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44</u>

5 0
2 years ago
4. Biotic factors that affect other organisms in an ecosystem include all but which of the following factors? a. Symbiosis b. Pr
GenaCL600 [577]

I think its d but im not sure

5 0
2 years ago
What is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water
Nastasia [14]

Answer:

4.6\,\,moL\,\,L^{-1}

Explanation:

Molarity refers to a measure of concentration.

Molarity = moles of solute/Litres of solution

Molarity refers to number of moles of solute present in this solution.

In order to find a solution's molarity, use value for the number of moles of solute  and the total volume of the solution expressed in liters

As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,

Molarity = \frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}

4 0
3 years ago
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