Answer: compaction, and cementation.
Explanation:
Answer:
32.1 × 10²³ formula units of CuCl₂
Explanation:
Given data:
Number of moles of CuCl₂ = 5.33 mol
Number of formula units of CuCl₂ = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of any substance contain 6.022 × 10²³ formula units thus,
5.33 moles of CuCl₂ = 5.33 ×6.022 × 10²³ formula units
32.1 × 10²³ formula units of CuCl₂
Answer:
![[OH^-]=1.7x10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.7x10%5E%7B-6%7DM)
Explanation:
Hello!
In this case, since the pOH of a solution can be computed when knowing the pH as shown below:

And therefore, the concentration of hydroxide ions based on the definition of pH:
![[OH^-]=10^{-pOH}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D)
In such a way, we obtain:
![[OH^-]=10^{-5.78}=1.7x10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-5.78%7D%3D1.7x10%5E%7B-6%7DM)
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A conversion factor is used to change the units of a measured quantity without changing its value. The unity bracket method of unit conversion consists of a fraction in which the denominator is equal to the numerator, but they are in different units.
Mass of Calcium phosphate : = 21127.7 g
<h3>Further explanation</h3>
Given
4.1 x 10²⁵ particles of Calcium phosphate
Required
mass
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
mol Calcium phosphate :
n = N : No
n = 4.1 x 10²⁵ : 6.02 x 10²³
n = 68.11
mass Calcium phosphate Ca3(PO4)2 :
= mol x MW
= 68.11 x 310.2 g/mol
= 21127.7 g
= 21.13 kg