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olga55 [171]
4 years ago
15

This when a satellite orbits in an oval-shaped path around a central object.

Physics
1 answer:
Ilya [14]4 years ago
8 0

Elliptical orbit.<<<<<<<<<<



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A violin string has a standard length of 32.8 cm. It sounds the musical note A (440 Hz) when played without fingering. How far f
Rus_ich [418]

Answer:

The finger has to be placed at 5.25cm

Explanation:

The steps and appropriate formula in musical instrument is as shown in the attachment.

5 0
3 years ago
1. An electrically charged atom ___________
dmitriy555 [2]

Answer:

Is called an Ion

Explanation:

7 0
3 years ago
Read 2 more answers
If a bowling ball is moving with acceleration of 15 m/s2 and has a mass of 10kg what is the force of the ball as it knocks down
Lina20 [59]

Answer:

150 newtons

Explanation:

F = ma

force = mass * acceleration

the mass is 10 kg, and the accelration is 15 m/s^2

10*15 = 150

the force unit that matches with meters/second and kg is newtons

F =ma

150 newtons = 10 kg * 15 m/s^2

6 0
3 years ago
A ball of mass 0.5kg is thrown at a man of mass 59.5kg standing on roller skates, at a speed of 5 m/s. It is stopped by the man.
Akimi4 [234]

The final velocity of the man standing on roller skates with the ball caught, after it is thrown at him at a speed of 5 m/s, is 0.042 m/s.                        

 

The velocity of the man with the ball can be calculated by conservation of linear momentum:

p_{i} = p_{f}

m_{b}v_{b_{i}} + m_{m}v_{m_{i}} = m_{b}v_{b_{f}} + m_{m}v_{m_{f}}

Where:

m_{b}: is the mass of the ball = 0.5 kg

m_{m}: is the <u>mass</u> of the man = 59.5 kg

v_{b_{i}}: is the initial velocity of the <u>ball</u> = 5 m/s

v_{m_{i}}: is the <u>initial velocity</u> if the <u>man</u> = 0 (he is standing still)

v_{b_{f}}: is the final velocity of the <u>ball</u> =?

v_{m_{f}}: is the <u>final velocity</u> of the <u>man</u> =?

Since the man catches the ball, his final velocity is the same that the final ball's velocity, so:

m_{b}v_{b_{i}} + m_{m}v_{m_{i}} = v_{f}(m_{b} + m_{m})

v_{f} = \frac{m_{b}v_{b_{i}} + m_{m}v_{m_{i}}}{m_{b} + m_{m}} = \frac{0.5 kg*5 m/s + 0}{0.5 kg + 59.5 kg} = 0.042 m/s

Therefore, the velocity of the man with the ball is 0.042 m/s.

Learn more about the conservation of linear momentum here:  

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/14283213?referrer=searchResults

I hope it helps you!  

4 0
2 years ago
1 point<br> You throw a ball up in the air with a velocity of 30 m/s. How high does it<br> go?
choli [55]

Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

4 0
3 years ago
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