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pogonyaev
3 years ago
11

What is the refractive index between glass and water?​

Physics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

The Refractive index of water is 1.3 and the refractive index of glass is 1.5.

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The number of sound waves per unit time is called what
Andreyy89

Answer:

Frequency

Explanation:

Hoped this helped

3 0
3 years ago
Which of the following best describes the function of a plant's flowers?
noname [10]

Answer: The function of a plant's flower is reproduce. Since the flowers are the reproductive organs of plant, they mediate the joining of the sperm, contained within pollen, to the ovules contained in the ovary.

Explanation:

8 0
3 years ago
You find a micrometer (a tool used to
MakcuM [25]

Explanation:

A micrometer is a measuring device or an instrument which is used to measure very minute measurements very accurately and precisely. It is mathematical tool used to provide accurate measurement for any mechanical components.

Now, if the micrometer that I have found is badly bent, it would provide faulty or wrong measurements both in terms of  precision and accuracy when compared to a high quality meter stick.

3 0
3 years ago
A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it
Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

F= ma (\rightarrow Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

\rho = \frac{m}{V} \Rightarrow m = \rho V

Part A) The buoyant force acting on the balloon is given as

F_b = ma

As mass is equal to the density and Volume and acceleration equal to Gravity constant

F_b = \rho V g

F_b = 1.2*323*9.8

F_b = 3798.5

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

F_{net} = F_b -W

F_{net} = F_b -(mg+\rho_H Vg)

F_{net} = 3798.5-(9.8*225*9.8*0.179*323)

F_{net} = 1030N

PART C) The additional mass that can the balloon support in equilibrium is given as

F_{net} = m' g

m' =\frac{F_{net}}{g}

m' = \frac{1030}{9.8}

m' = 105Kg

4 0
4 years ago
what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three
grin007 [14]

Answer:

Approximately 5.11 \times 10^{-19}\; {\rm J}.

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}.

Look up the speed of light in vacuum: c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}.

Look up Planck's constant: h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}.

Apply the Rydberg formula to find the wavelength \lambda (in vacuum) of the photon in question:

\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}.

The frequency of that photon would be:

\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}.

Combine this expression with the Rydberg formula to find the frequency of this photon:

\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}.

Apply the Einstein-Planck equation to find the energy of this photon:

\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}.

(Rounded to three significant figures.)

6 0
2 years ago
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