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pogonyaev
3 years ago
11

What is the refractive index between glass and water?​

Physics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

The Refractive index of water is 1.3 and the refractive index of glass is 1.5.

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Pls help me w this, I've been doing this since 5 minutes ago​
natka813 [3]

Answer:

t=0.0625s

Explanation:

F=number of swings/time taken

DATA

Frequency=4.0Hz

number of swings from Q to R

=1/4

time taken=?

Frequency=number of swings/time taken

make t the subject of the formula

t=n/f

substitute the given date

t=0.25/4.0

t=0.0625s

option A is collect

4 0
3 years ago
A 39.7 n object is in free fall. what is the magnitude of the net force which acts on the object? answer in units of n.
Vika [28.1K]
If there is no air resistance, the value would still be the same. So therefore, the answer is 39.7 N.
Supposing that there is an air resistance of 19.8 N.With a 19.8 N air resistance: ∑F = 39.7 N - 19.8 N = 19.9 N would be the net force. The important point here is that the force of gravity equivalent the weight of the object.
6 0
3 years ago
Which of the following is NOT usually published with a scientific report?
dusya [7]

C cost (I need points)

5 0
3 years ago
Humans and fish brains are similar because they both have a?
velikii [3]

Answer:

it is because they can store and retrieve informatiion just like human beings

4 0
3 years ago
Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h
padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

v=\sqrt{\frac{2GM}{R}}

where G is the universal gravitational constant, M is the mass of the asteroid and R is the radius

and since the scape velocity is 50m/s:

50m/s=\sqrt{\frac{2GM}{R}}

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: 2M

and the radius is: 2R

inserting these values into the formula for escape velocity:

v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }

and we have found that 50m/s=\sqrt{\frac{2GM}{R}}, so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

7 0
3 years ago
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