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ruslelena [56]
3 years ago
8

If the force of static friction on a crate is 67 N and the weight of the create is 289 N, what is the coefficient of static fric

tion?
a
19363
b
0.23
c
4.31
d
222
Physics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

B) μ = 0.23

Explanation:

The coefficient of friction is equal to μ = F / N where μ (mu) is the coefficient of friction, F is the friction force, and N is the normal force (the force of an object being applied onto the earth by gravity).

F, the friction force, is given as 67 N

Since the weight of the crate is 289 N, that means the normal force is 289 N.

This means that the coefficient of friction is  μ = F / N = 67 N / 289 N = 0.23183391 = 0.23

Therefore, B is the correct answer

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The speed of A and B immediately after collision is 5.28m/s

<u>Explanation:</u>

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Mass of B is 5155kg

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Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

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4 0
3 years ago
A hockey puck slides across the ice at a constant velocity. Is the sliding puck in equilibrium? Why or why not?
geniusboy [140]

Answer:

Since the hockey puck is moving at constant velocity

So here we will have

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