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Ede4ka [16]
3 years ago
6

Given that the electronic configuration of an element X is 1s2 2s2 2p6 3s2 3p4,it can be deduced that X:

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

Option A

Explanation:

The element X belongs to

=> Period 3 (Because it's valence shell is 3)

=> Group VI (Because electrons in the valence shell , 2+4 = 6)

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Before we can analyze the alum crystal it is
dusya [7]

Answer: TRUE

Explanation:

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3 years ago
The gas SF6 is used to trace air flows because it is non-toxic and can be detected selectively in air at a concentration of 1.0
melomori [17]

SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.

First, we will calculate the partial pressure of SF₆  using the following expression.

pSF_6 = P \times \frac{ppb}{10^{9} }

where,

  • pSF₆: partial pressure of SF₆
  • P: total pressure of air (we will assume it is 1 atm)
  • ppb: concentration of SF₆ in parts per billion

pSF_6 = P \times \frac{ppb}{10^{9} } = 1 atm \times \frac{1.0 ppb}{10^{9} } = 1.0 \times 10^{-9} atm

Then, we will convert 1.0 cm³ to L using the following conversion factors:

  • 1 cm³ = 1 mL
  • 1 L = 1000 mL

1.0 cm^{3} \times \frac{1mL}{1cm^{3}} \times \frac{1L}{1000 mL} = 1.0 \times 10^{-3} L

Next, we will convert 46 °C to Kelvin using the following expression.

K = \° C + 273.15 = 46 + 273.15 = 319 K

Afterward, we calculate the moles (n) of sulfur hexafluoride using the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T}  = \frac{1.0 \times 10^{-9} atm  \times 1.0 \times 10^{-3} L}{(0.082 atm.L/mol.K) \times 319 K} = 3.8 \times 10^{-14} mol

Finally, we will convert 3.8 × 10⁻¹⁴ mol to molecules using Avogadro's number.

3.8 \times 10^{-14} mol \times \frac{6.02 \times 10^{23} molecules  }{mol} = 2.3 \times 10^{10} molecules

SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.

You can learn more about partial pressure here: brainly.com/question/13199169

6 0
3 years ago
A student tests elements and finds it to be malleable, a good conductor of electricity, but is not magnetic. Which is most likel
ELEN [110]

Answer:

copper

Explanation:

5 0
3 years ago
Si tienes una disolución al 30 % en masa, ¿Cuál sería la nueva concentración si añades agua suficiente hasta duplicar su volumen
Alika [10]

Answer:

17.6% en masa será la nueva concentración de la solución

Explanation:

Una disolución al 30% en masa contiene 30g de soluto en 100g de solución (Solvente + soluto). Así, la masa de solvente (Agua) es:

100g - 30g = 70g

Dado que la densidad del agua es de 1g/mL, 70g de agua ocupan 70mL.

Si el volumen se duplica, habrán 140mL de agua = 140g de solvente.

Así, la masa total de la solución será 30g + 140g = 170g y el porcentaje en masa será:

30g soluto / 170g solución × 100 =

<h3>17.6% en masa será la nueva concentración de la solución</h3>
4 0
3 years ago
What function is most affected if the sepal of a flower is damaged by air pollution?
stepladder [879]

Answer:answer in explanation try to understand dear

Explanation:Air pollutants have a negative impact on plant growth, primarily through interfering with resource accumulation. Once leaves are in close contact with the atmosphere, many air pollutants, such as O3 and NOx, affect the metabolic function of the leaves and interfere with net carbon fixation by the plant canopy.

6 0
3 years ago
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