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BaLLatris [955]
3 years ago
8

Determine the molar solubility for pb3(po4)2 in pure water. ksp for pb3(po4)2 is 1.0 x 10-54.

Chemistry
1 answer:
hoa [83]3 years ago
7 0
Dissociation of Pb₃(PO₄)₂ is;
                       Pb₃(PO₄)₂(s)     ⇆      3Pb²⁺(aq)     +     2PO₄³⁻(aq)
initial                                                    -                          -
change               -X                            +3X                     +2X
Equilibrium                                          3X                        2X

Ksp            =       [Pb²⁺(aq)]³ [PO₄³⁻(aq)]²
1.0 x 10⁻⁵⁴ =         (3X)³ (2X)²
1.0 x 10⁻⁵⁴ =        108X⁵
         X      =        6.21 x 10⁻¹² M

Hence the molar solubility of Pb₃(PO₄)₂ is 6.21 x 10⁻¹² M.
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