A sample of rutile, an ore of titanium consisting principally of TiO2(s), was found to be 65.2% TiO2(s) by mass, with the remainder being sand impurities. what is the minimum number of metric tons of the ore that must be processed to obtain 10.0 metric tons of titanium
Explanation:
Ore contains ---- 65.2% 
Mass% of titanium in TiO2 can be calculated as shown below:
Given 10.0 metric tons of titanium is required.
The mass of ore that should be processed can be calculated as shown below:
Mass of Ti = ore x TiO2 % x Ti mass %
10.0 x 1000 kg = M (mass of ore) x (65.2/100) x (59.9/100) Ti
=>M=(10.0 metric tons) / (0.652 x 0.599)
=>M=25.6 metric tons
Hence, the mass of ore required is 25.6 metric tons.
A change in pressure will affect the equilibrium position of the reaction if one or more of the reactants or products are in the gaseous phase.
Le Chatelier's principle states that whenever a change is brought about to a system under chemical equilibrium, the equilibrium shifts in a manner to reverse this change. So if the pressure of a reaction mixture is increased, the equilibrium will shift towards the side with the lower number of molecules, and if the pressure is reduced, the equilibrium will shift to the side with the greater number of molecules.
It’s b for sure that’s the answer
Answer:
The answer to your question is 25 grams
Explanation:
Data
half-life = 5730 years
sample = 200 g
after 3 half-lives
Process
Calculate the amount of sample after one, two and three half-lives.
After each half-life, that of sample is half the previous amount.
Number of half-lives Amount of sample
0 200 g
1 100 g
2 50 g
3 25 g
