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2 years ago

6.How many moles of gas would be in contained in a 11.2 L container that is at a

Chemistry

1 answer:

qaws [65]2 years ago

4 0

0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated using the following expression:

PV = nRT

Where;

p = pressure (atm)
v = volume (L)
n = number of moles
R = gas law constant
T = temperature

0.75 × 11.2 = n × 0.0821 × 300

8.4 = 24.63n

n = 8.4 ÷ 24.63

n = 0.34 moles

Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

Learn more about number of moles at: brainly.com/question/1190311

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A sample of copper metal has a mass of 848 grams. How many moles of copper are in the sample? 13.34 mol Cu, 13.3 mol Cu, 12.9 mo

ANTONII [103]

Answer:

$mol_{Cu}=13.34molCu$

Explanation:

Hello,

In this case, as the atomic mass of coppe is 63.546 g/mol, with the given mass with can compute the moles as shown below:

$mol_{Cu}=848gCu*\frac{1molCu}{63.546 gCu} \\\\mol_{Cu}=13.34molCu$

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4 years ago

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3 years ago

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Use the ruler to determine the length of this object. Record your answer to the nearest tenth. The object is ____ long.

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3 years ago

There are two opposing processes that occur in a solution in contact with undissolved solute. These are dissolving and ________.

Alex777 [14]

Answer:

c. crystallization

Explanation:

The opposing process that occur in a solution in contact with undissolved solute are dissolution and crystallization.

In the dissolution process the solid substance coverts into liquid state and mixes with solution. Whereas in Crystallization the the chemical is converted from the liquid solution to solid crystal state.

3 0

3 years ago

For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f

OverLord2011 [107]

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

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3 years ago