All categories

3 years ago

Which shows 522 − 482 being evaluated using the difference of perfect squares method?

2 answers:

8 0

52² − 48² = (2704 + 2304)(2704 − 2304) = 2,003,200

52² − 48² = (52 + 48)(52 − 48) = 100 * 4 = 400
a² - b² = (a +b)*(a-b)

52² − 48² = 2704 − 2304 = 400

52² − 48² = (52 − 48)² = (4)² = 16

attashe74 [19]3 years ago

3 0

Answer:

the answer is

a.522 − 482 = (2704 + 2304)(2704 − 2304) = 2,003,200

Step-by-step explanation:

i got it right in the test i just took

You might be interested in

11) Write the explicit formula

Illusion [34]

Answer:

365

Step-by-step explanation:

tn = t1 + (n - 1)(d)

t(47) = -3 + (47 - 1)(8)

t(47) = -3 + (46)(8)

t(47) = -3 + 368

t(47) = 365

6 0

2 years ago

What is the vertex of the graph of the function below? y = x2 + 8x + 12

Vera_Pavlovna [14]

Hello,

$The\,\,formula\,\,for\,\,the\,\,vertex\,\,of\,\,a\,\,quadratic\,\,equation\,\,is: \\ V=( -\frac{b}{2a},f(-\frac{b}{2a}) )$

That means that we must first obtain x, then we replace x in the function to get y, so:

$x=- \frac{b}{2a} \\ \\ x=- \frac{8}{2*(1)} \\ \\ \boxed{x=-4} \\ \\ Reeplacing \,\,x: \\ y=(-4)^{2} +8*(-4)+12 \\ y=16-32+12 \\ \boxed{y=-4}$

Answer: V=(-4 , -4)

5 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

2 years ago

Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity

aleksklad [387]

$\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)$

7 0

1 year ago

8a-2b+12a-2a-4b show how to simplify the expression. Write the answer the factored form

Trava [24]

$8a-2b+12a-2a-4b=8a+12a-2a-2b-4b=18a-6b$

5 0

3 years ago

Read 2 more answers