An icy object moving through space in a highly eccentric orbit is called a

Identify where the solid would be found after distillation is complete.

dimaraw [331]

Bottom of the distillation flask

Explanation:

The solid in the mixture to be separate would be found at the bottom of the distillation flask.

Distillation is a separation technique for differentiating the components of mixtures based on the differences in their boiling points.

Distillation is used to recover solvents from solution.
The solutes are then left behind in the flask as the solvent boils out as vapor.
The solution is boiled in a distillation flask to vaporize the solvent.
The vapor is made to condense back into liquid by means of a condenser.
The pure liquid called distillate is collected in the receiver.
The solute which is the solid remains in the distillation flask

learn more:

Heterogeneous mixtures brainly.com/question/1446244

Pure substances brainly.com/question/1832352

#learnwithBrainly

8 0

3 years ago

Find an expression for the electric field E⃗ at the center of the semicircle. Hint: A small piece of arc length Δs spans a small

Hatshy [7]

Answer:

Electric Field a the centre $E=\dfrac{Q}{2\pi^2\epsilon_0 R^2}(-\vec j)$

Explanation:

<u>Given:</u>

Total charge on the semicircle =Q

Radius of the semicircle=R

Let consider a elemental charge on the semicircle at an angle $\theta\\$ with the horizontal. Since the The charge distribution is symmetrical about y axis so the there will symmetrical charge on other side. The horizontal component will cancel out each other and vertical component will get added so let dE be the electric Field due to elemental charge

Let $\lambda$ be the charge per unit length such that $\lambda=\dfrac{Q}{\pi R}$

$k=\dfrac{1}{4\pi \epsilon_0}$

Total Electric Field at the centre

$=2dE\sin\theta\\=2\dfrac{k\lambda }{R}\int \sin \theta d\theta\\$

integrating 0 to $\dfrac{\pi}{2}$

$E=\dfrac{2k\lambda}{R}(-\vec j)$

$E=\dfrac{Q}{2\pi^2\epsilon_0 R^2}(-\vec j)$

So the Electric field at the centre is calculated.

7 0

3 years ago

Who gains altitude more quickly, a pilot traveling 400 mph and rising at an angle of 30°, or a pilot traveling 300 mph and risin

Basile [38]

The rate of altitude increase is equivalent to the vertical component of the pilot's velocity. Let the first pilot's velocity be A and the second's be B.
Ay = Asin(∅)
Ay = 400sin(30)
Ay = 200 mph

By = Bsin(∅)
By = 300sin(40)
By = 192.8 mph

200 - 192.8 = 7.2 mph
The first pilot gains altitude faster by 7.2 mph than the second pilot.

4 0

3 years ago

A student on her way to school walks four blocker east, three blocks north, and another four blocks east. Compared to the distan

nata0808 [166]

Answer:

The magnitude of the student's displacement is less than the distance she walked.

Walking: 11 Blocks

Displacement: 8.54 Blocks

Explanation:

See the attached diagram. The unit of length is blocks. We can add the actual blocks walked as shown. She walked a total of 11 blocks.

Her displacement is the distance measured directly from where she started (line A). Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines. The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.

That result is 8.54 Blocks, a shorter distance, once she earns her wings.

3 0

2 years ago

a spring length of 20cm, the vibrational frequency of the spring is 15 Hz, about that spring period is?

nlexa [21]

I gave u something that mite help

5 0

3 years ago