An icy object moving through space in a highly eccentric orbit is called a

In an experiment, the independent variable is what?

ella [17]

A variable is any factor, trait, or condition that can exist in differing amounts or types. An experiment usually has three kinds of variables: independent, dependent, and controlled. The independent variable is the one that is changed by the scientist.

7 0

3 years ago

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Q2/Deceleration of a particle is based on relation a=-3 v² m/s² where v in m/s. If it moves along a straight line and has veloci

kozerog [31]

Explanation:

Given: a = -3v^2

By definition, the acceleration is the time derivative of velocity v:

$a = \frac{dv}{dt} = - 3 {v}^{2}$

Re-arranging the expression above, we get

$\frac{dv}{ {v}^{2} } = - 3dt$

Integrating this expression, we get

$\int \frac{dv}{ {v}^{2} } = \int {v}^{ - 2}dv = - 3\int dt$

$- \frac{1}{v} = - 3t + k$

Since v = 10 when t = 0, that gives us k = -1/10. The expression for v can then be written as

$- \frac{1}{v} = - 3t - \frac{1}{10} = - ( \frac{30 + 1}{10} )$

or

$v = \frac{10}{30t +1 }$

We also know that

$v = \frac{ds}{dt}$

or

$ds = vdt = \frac{10 \: dt}{30t + 1}$

We can integrate this to get s:

$s = \int v \: dt = \int ( \frac{10}{30t + 1}) \: dt = 10 \int \frac{dt}{30t + 1}$

Let u = 30t +1

du = 30dt

so

$\int \frac{dt}{30t + 1} = \frac{1}{30} \int \frac{du}{u} = \frac{1}{30}\ln |u| + k$

$= \frac{1}{30}\ln |30t + 1| + k$

So we can now write s as

$s = \frac{1}{3}\ln |30t + 1| + k$

We know that when t = 0, s = 8 m, therefore k = 8 m.

$s = \frac{1}{3}\ln |30t + 1| + 8$

Next, we need to find the position and velocity at t = 3 s. At t = 3 s,

$v = \frac{10}{30(3) +1 } = \frac{10}{91}\frac{m}{s} = 0.11 \: \frac{m}{s}$

$s = \frac{1}{3}\ln |30(3) + 1| + 8 = 9.5 \: m$

Note: velocity approaches zero as t --> $\infty$

5 0

3 years ago

Which is a group pragram acoholics recover in

Svetradugi [14.3K]

A group program alcoholics recover in is A-A

4 0

3 years ago

SOHCAHTOA MATH REVIEW Find the angle x from the diagram above

mestny [16]

Explanation:

Hey there!

Here,

It is a Right angled triangle.

Now, Taking angle x as a reference angle.

We get,

perpendicular (p) = 24.

Hypotenuse (h) = 29.

Using sin ratio we get.

$\sin( \alpha ) = \frac{p }{h}$

Now, keep values and simplify them.

$\sin(x) = \frac{24}{29}$

sinx = 0.8275.

$x = { \sin }^{ - 1} (0.8275)$

Therefore the value of x is 55.842°. Or 55°.

Hope it helps....

5 0

3 years ago

HELP ASAP

velikii [3]

Answer:

A. negatively charged are deposited on the belt, which deposits positive charges on the metal ball.

Explanation:

Negatively charged ions are injected at one end of thebelt towards the high potntial terminal, where they are acclerated by attractive forces towards the terminal. When the particles reach the terminal, they are stripped of some electrons to make them positively charged.

5 0

3 years ago